Skip to content
Related Articles
Get the best out of our app
Open App

Related Articles

UGC-NET | UGC NET CS 2017 Jan – III | Question 50

Improve Article
Save Article
Like Article
Improve Article
Save Article
Like Article

Consider a disk queue with I/O requests on the following cylinders in their arriving order:

6, 10, 12, 54, 97, 73, 128, 15, 44, 110, 34, 45 

The disk head is assumed to be at cylinder 23 and moving in the direction of decreasing number of cylinders. Total number of cylinders in the disk is 150. The disk head movement using SCAN-scheduling algorithm is:
(A) 172
(B) 173
(C) 227
(D) 228


Explanation: According to SCAN disk scheduling algorithm:

When it completed its last given sequence from input, it stops.
So, total disk head movement = 23+128 = 151.

So, none option matches.

Quiz of this Question

My Personal Notes arrow_drop_up
Last Updated : 27 Nov, 2018
Like Article
Save Article
Similar Reads