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UGC-NET | UGC NET CS 2015 Jun – III | Question 14

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Discuss

Consider a triangle A(0,0), B(1,1) and C(5,2). The triangle has to be rotated by an angle of 458 about the point P(21, 21). What shall be the coordinates of the new triangle?
(A) $A'= (1,\sqrt{2} -1), B' = (-1, 2\sqrt{2 }- 1) and C' = (3\sqrt{2}-1, \frac{9}{2}\sqrt{2}-1)$
(B) $A'= (1,\sqrt{2} -1), B' = ( 2\sqrt{2 }- 1, -1) and C' = (3\sqrt{2}-1, \frac{9}{2}\sqrt{2}-1)$
(C) $A'= (-1,\sqrt{2} -1), B' = ( -1, 2\sqrt{2 }- 1) and C' = (3\sqrt{2}-1, \frac{9}{2}\sqrt{2}-1)$
(D) $A'= (\sqrt{2} -1, -1), B' = ( -1, 2\sqrt{2 }- 1) and C' = (3\sqrt{2}-1, \frac{9}{2}\sqrt{2}-1)$

Answer: (C)

Explanation:

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Last Updated : 13 Jun, 2018

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