UGC NET CS 2017 Jan – II

  • Last Updated : 18 Oct, 2019 



 
  
        
    
   
  

  
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Question 1
Consider a sequence F00 defined as :
 F00(0) = 1, F00(1) = 1
 F00(n) = 10 ∗ F00(n – 1) + 100
F00(n – 2) for n ≥ 2
 Then what shall be the set of values of the sequence F00 ? 
A
(1, 110, 1200) 
B
(1, 110, 600, 1200) 
C
(1, 2, 55, 110, 600, 1200) 
D
(1, 55, 110, 600, 1200) 
UGC NET CS 2017 Jan - II    Top MCQs on Dynamic Programming with Answers    
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Question 1 Explanation: 
 
 F00(0) = 1, F00(1) = 1
 F00(n) = 10 ∗ F00(n – 1) + 100
 F00(2) = 10 * F00(1) + 100
 = 10 * 1 + 100
 = 10 + 100
 = 110
Similarly:
F00(3) = 10 * F00(2) + 100
 = 10 * 110 + 100
 = 1100 + 100
 = 1200
The sequence will be (1, 110, 1200).

So, (A) will be the answer.
Question 2
Match the following : 
 2
A
(1)
B
(2)
C
(3)
D
(4)
UGC NET CS 2017 Jan - II    
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Question 2 Explanation: 
 
  1. Absurd means Clearly impossible being contrary to some evident truth.
    2. 

  2. Ambiguous Capable of more than one interpretation or meaning. 
    3. 

  3. An assertion that is accepted and used without a proof.
    4. 

  4. Conjecture An opinion preferably based on some experience or wisdom

So, option (A) is correct.

Question 3
The functions mapping R into R are defined as :
 f(x) = x3 – 4x, g(x) = 1/(x2 + 1) and h(x) = x4.
 Then find the value of the following composite functions :
 hog(x) and hogof(x) 
A
(x2 + 1)4 and [(x3 – 4x)2 + 1]4
B
(x2 + 1)4 and [(x3 – 4x)2 + 1]-4
C
(x2 + 1)-4 and [(x3 – 4x)2 + 1]4
D
(x2 + 1)-4 and [(x3 – 4x)2 + 1]-4
UGC NET CS 2017 Jan - II    Numerical Methods and Calculus    
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Question 3 Explanation: 
 
 f(x) = x3 – 4x, g(x) = 1/(x2 + 1) and h(x) = x4
 hog(x) = [g(x)]4
        =  [1/(x2 + 1)]4
        =  [(x2 + 1)-1]4
        =  [(x2 + 1)]-4
Similarly:
hogof(x) = [gof(x)]4
         = [(f(x)2 + 1)]-4
         =  [((x3 – 4x)2 + 1)]-4


So, option (D) is correct.
Question 4


How many multiples of 6 are there between the following pairs of numbers ? 0 and 100 and –6 and 34


A


16 and 6


B


17 and 6


C


17 and 7


D


16 and 7


UGC NET CS 2017 Jan - II    General Aptitude    
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Question 4 Explanation: 
 

Between 0 and 100 multiple of 6 are: 0,6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96 ie. 17 multiple. Between -6 and 34 multiple of 6 are: -6, 0, 6, 12, 18, 24, 30. ie. 7 multiple. 



So,option (C) is correct.


Question 5
Consider a Hamiltonian Graph G with no loops or parallel edges and with |V(G)| = n ≥ 3.
Then which of the following is true ? 
A
deg(v) ≥n/2 for each vertex v.
B
|E(G)| ≥1/2(n – 1) (n – 2) + 2
C
deg (v) + deg(w) ≥ n whenever v and w are not connected by an edge
D
All of the above
UGC NET CS 2017 Jan - II    Top MCQs on Graph Theory in Mathematics    
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Question 6
In propositional logic if (P → Q) ∧ (R → S) and (P ∨ R) are two premises such that
(P → Q) ∧ (R → S)
P ∨ R
Y
 Y is the premise : 
A
P ∨ R
B
P ∨ S
C
Q ∨ R
D
Q ∨ S
UGC NET CS 2017 Jan - II    Propositional and First Order Logic.    
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Question 7
ECL is the fastest of all logic families. High speed in ECL is possible because transistors are used in difference amplifier configuration, in which they are never driven into ____. 
A
Race condition
B
Saturation 
C
Delay
D
High impedance 
UGC NET CS 2017 Jan - II    Propositional and First Order Logic.    
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Question 8
Convert the octal number 0.4051 into its equivalent decimal number. 
A
0.5100098 
B
0.2096
C
0.52
D
0.4192 
UGC NET CS 2017 Jan - II    Digital Logic & Number representation    Number Representation    
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Question 8 Explanation: 
 Convert 0.4051 into decimal in traditional way:

i.e.  4 * 8-1 + 0 * 8-2 + 5 * 8-3 + 1 * 8-4
= 0.5100098
 
So, option (A) is correct.
Question 9
The hexadecimal equivalent of the octal number 2357 is : 
A
2EE 
B
2FF
C
4EF
D
4FE
UGC NET CS 2017 Jan - II    Digital Logic & Number representation    Number Representation    
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Question 9 Explanation: 
 First we will convert 2357 into binary: 010 011 101 111 now we will group this binary number into group of 4 → 0100 1110 1111 now place the hexadecimal equivalent ie 1111 - F, 1110 - E, 0100 - 4. Hexadecimal no is 4EF.
So, option (E) is correct. 
Question 10
Which of the following cannot be passed to a function in C++ ? 
A
Constant
B
Structure 
C
Array
D
Header file 
UGC NET CS 2017 Jan - II    Class and Object    
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Question 10 Explanation: 
 Header file can not be passed to a function in C++. While array, constant and structure can be passed into a function.
So, option (D) is correct.
                
    
  

    
    
   
  
    

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