Trie | (Display Content)
Trie is an efficient information retrieval data structure. In our previous post on trie we have discussed about basics of trie and how to insert and search a key in trie. In this post we will discuss about displaying all of the content of a trie. That is, to display all of the keys present in the Trie.
Examples:
Input: If Trie is root / \ \ t a b | | | h n y | | \ | e s y e / | | i r w | | | r e e | r Output: Contents of Trie: answer any bye their there
The idea to do this is to start traversing from the root node of trie, whenever we find a NON-NULL child node, we add parent key of child node in the “string str” at the current index(level) and then recursively call the same process for the child node and same goes on till we find the node which is a leafnode, which actually marks the end of the string.
Below is the C++ implementation of above idea:
CPP
// CPP program to display content of Trie #include <iostream> #include <string.h> #define alpha_size 26 #define ARRAY_SIZE(a) sizeof(a) / sizeof(a[0]) using namespace std; // Trie node struct TrieNode { struct TrieNode* children[alpha_size]; bool isLeaf; }; // Returns new trie node (initialized to NULLs) struct TrieNode* createNode() { struct TrieNode* pNode = new TrieNode; for ( int i = 0; i < alpha_size; i++) pNode->children[i] = NULL; pNode->isLeaf = false ; return pNode; }; // function to insert a node in Trie void insert_node( struct TrieNode* root, char * key) { int level; int length = strlen (key); struct TrieNode* pCrawl = root; for (level = 0; level < length; level++) { int index = key[level] - 'a' ; if (pCrawl->children[index] == NULL) pCrawl->children[index] = createNode(); pCrawl = pCrawl->children[index]; } pCrawl->isLeaf = true ; } // function to check if current node is leaf node or not bool isLeafNode( struct TrieNode* root) { return root->isLeaf != false ; } // function to display the content of Trie void display( struct TrieNode* root, char str[], int level) { // If node is leaf node, it indicates end // of string, so a null character is added // and string is displayed if (isLeafNode(root)) { str[level] = '\0' ; cout << str << endl; } int i; for (i = 0; i < alpha_size; i++) { // if NON NULL child is found // add parent key to str and // call the display function recursively // for child node if (root->children[i]) { str[level] = i + 'a' ; display(root->children[i], str, level + 1); } } } // Driver program to test above functions int main() { // Keys to be inserted in Trie char keys[][8] = { "the" , "a" , "there" , "answer" , "any" , "by" , "bye" , "their" }; struct TrieNode* root = createNode(); // Inserting keys in Trie for ( int j = 0; j < ARRAY_SIZE(keys); j++) insert_node(root, keys[j]); int level = 0; char str[20]; // Displaying content of Trie cout << "Content of Trie: " << endl; display(root, str, level); } |
Python3
##Display words in a trie (recursive approach) class TrieNode: def __init__( self ): self .children = [ None ] * 26 self .isEndOfWord = False class Trie: def __init__( self ): self .root = self .getNode() def getNode( self ): return TrieNode() def _charToIndex( self ,ch): return ord (ch) - ord ( 'a' ) def search( self ,key): pCrawl = self .root length = len (key) for level in range (length): index = self ._charToIndex(key[level]) if not pCrawl.children[index]: return False pCrawl = pCrawl.children[index] return pCrawl.isEndOfWord def insert( self ,key): pCrawl = self .root length = len (key) for level in range (length): index = self ._charToIndex(key[level]) if not pCrawl.children[index]: pCrawl.children[index] = self .getNode() pCrawl = pCrawl.children[index] pCrawl.isEndOfWord = True def delete( self ,key): queue = [] pCrawl = self .root prev = self .root length = len (key) for level in range (length): index = self ._charToIndex(key[level]) if not pCrawl.children[index]: return if pCrawl.isEndOfWord: queue.append([pCrawl,level]) pCrawl = pCrawl.children[index] if pCrawl.isEndOfWord = = False : return ##If is a prefix of another tree, just change leaf flag = False for i in range ( 26 ): if pCrawl.children[index]: flag = True if flag: pCrawl.isEndOfWord = = False return ##If not a prefix but a tree longer than others, delete until isEndOfWord == True again/reach root(a unique trie) if len (queue) = = 0 : index = self ._charToIndex(key[ 0 ]) self .root.children[index] = None return pCrawl,level = queue.pop() index = self ._charToIndex(key[level]) pCrawl.children[index] = None def haschild( self ,node): for i in range ( 26 ): if node.children[i]: return True return False def displayUtil( self ,visited,node, str ): index = 0 while index< 26 : if node.children[index]: str + = chr ( 97 + index) #print(2,str) if node.children[index].isEndOfWord = = False : self .displayUtil(visited,node.children[index], str ) str = str [ 0 : ( len ( str ) - 1 )] else : if str not in visited: visited.append( str ) if self .haschild(node.children[index]): self .displayUtil(visited,node.children[index], str ) str = str [ 0 : ( len ( str ) - 1 )] index + = 1 def display( self ): visited = [] str = '' self .displayUtil(visited, self .root, str ) print ( "Content of Trie:" ) for i in range ( len (visited)): print (visited[i]) keys = [ "the" , "a" , "there" , "bye" , "any" , "by" , "their" , "answer" ] output = [ "Not present in trie" , "Present in trie" ] t = Trie() for key in keys: t.insert(key) t.display() #This code is contributed by Zhaoxin Ban |
Output:
Content of Trie: a answer any by bye the their there
NOTE: The above algorithm displays the content of Trie in Lexicographically Sorted order.
Some useful applications of Trie are:
- Implementing Auto-Correct and Auto complete Features
- Implementing a Dictionary
This article is contributed by Yash Singla. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
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