# Total sum except adjacent of a given node in a Binary Tree

• Difficulty Level : Easy
• Last Updated : 30 Aug, 2022

Given a BT and a key Node, find the total sum in BT, except those nodes which are adjacent to key Node.

Examples:

1. Traverse the tree using pre-order.
2. If the current node is adjacent to the key then do not add it to the final sum.
3. If the current node is the key then do not add its children to the final sum.
4. If the key is not present then return the sum of all nodes.

Implementation:

## C++

 `// C++ program to find total sum except a given Node in BT` `#include ` `using` `namespace` `std;`   `struct` `Node {` `    ``int` `data;` `    ``struct` `Node *left, *right;` `};`   `// insertion of Node in Tree` `Node* getNode(``int` `n)` `{` `    ``struct` `Node* root = ``new` `Node;` `    ``root->data = n;` `    ``root->left = NULL;` `    ``root->right = NULL;` `    ``return` `root;` `}`   `// sum of all element except those which are adjacent to key Node` `void` `find_sum(Node* root, ``int` `key, ``int``& sum, ``bool` `incl)` `{` `    ``if` `(root) {` `        ``if` `(incl) {` `            ``sum += root->data;`   `            ``if` `(root->left && root->left->data == key) {` `                ``sum -= root->data;` `            ``}` `            ``else` `if` `(root->right && root->right->data == key) {` `                ``sum -= root->data;` `            ``}` `        ``}`   `        ``incl = root->data == key ? ``false` `: ``true``;` `        ``find_sum(root->left, key, sum, incl);` `        ``find_sum(root->right, key, sum, incl);` `    ``}` `}`   `// Driver code` `int` `main()` `{` `    ``struct` `Node* root = getNode(15);` `    ``root->left = getNode(13);` `    ``root->left->left = getNode(12);` `    ``root->left->left->left = getNode(11);` `    ``root->left->right = getNode(14);` `    ``root->right = getNode(20);` `    ``root->right->left = getNode(18);` `    ``root->right->right = getNode(24);` `    ``root->right->right->left = getNode(23);` `    ``root->right->right->right = getNode(25);` `    ``int` `key = 20;` `    ``int` `sum = 0;` `    ``find_sum(root, key, sum, ``true``);` `    ``printf``(``"%d "``, sum);` `    ``return` `0;` `}`

## Java

 `// Java program to find total sum except a given Node in BT` `import` `java.util.*;` `class` `Node` `{` `    ``int` `data;` `    ``Node left, right;` `    `  `    ``// insertion of Node in Tree` `    ``Node(``int` `key)` `    ``{` `        ``data = key;` `        ``left = right = ``null``;` `    ``}` `}` `class` `GFG` `{` `    ``static` `class` `cal` `   ``{` `      ``int` `sum = ``0``;` `    ``}` `    `  `    ``// sum of all element except those which are adjacent to key Node` `    ``public` `static` `void` `find_sum(Node root, ``int` `key, cal r, ``boolean` `incl)` `    ``{` `        ``if``(root != ``null``)` `        ``{` `            ``if``(incl == ``true``)` `            ``{` `                ``r.sum += root.data;` `                ``if``((root.left != ``null``) && (root.left.data == key))` `                        ``{` `               ``r.sum -= root.data;` `            ``}` `                 ``else` `                 ``if``((root.right != ``null``) && (root.right.data == key))` `                       ``{` `                   ``r.sum -= root.data;` `            ``}` `                `  `            ``}` `            `  `            ``if``(root.data == key)` `                ``incl = ``false``;` `                ``else` `                ``incl = ``true``;` `                `  `        ``find_sum(root.left, key, r, incl);` `        ``find_sum(root.right, key, r, incl);` `        ``}` `    ``}` `    `  `// Driver code` `public` `static` `void` `main (String[] args) ` `{` `        ``Node root = ``new` `Node(``15``);` `        ``root.left = ``new` `Node(``13``);` `        ``root.left.left = ``new` `Node(``12``);` `        ``root.left.left.left = ``new` `Node(``11``);` `        ``root.left.right = ``new` `Node(``14``);` `        ``root.right = ``new` `Node(``20``);` `        ``root.right.left = ``new` `Node(``18``);` `        ``root.right.right = ``new` `Node(``24``);` `        ``root.right.right.right = ``new` `Node(``25``);` `        ``root.right.right.left = ``new` `Node(``23``);` `        ``int` `key = ``20``;` `         ``cal obj = ``new` `cal();` `        ``find_sum(root, key, obj, ``true``);` `        ``System.out.print(obj.sum);` `    ``}` `    `  `}`

## Python

 `# Python program to find total ` `# sum except a given Node in BT` `class` `Node:` `    `  `    ``def` `__init__(``self``, data):` `      `  `        ``self``.left ``=` `None` `        ``self``.right ``=` `None` `        ``self``.data ``=` `data`   `# Insertion of Node in Tree` `def` `getNode(n):` `    `  `    ``root ``=` `Node(n)` `    ``return` `root`   `# sum of all element except ` `# those which are adjacent ` `# to key Node` `def` `find_sum(root, key, ` `             ``sum``, incl):`   `    ``if` `(root):        ` `        ``if``(incl):            ` `            ``sum` `+``=` `root.data;`   `            ``if` `(root.left ``and` `                ``root.left.data ``=``=` `key):` `                ``sum` `-``=` `root.data;` `            `  `            ``elif` `(root.right ``and` `                  ``root.right.data ``=``=` `key):` `                ``sum` `-``=` `root.data;` `        `  `        ``if` `root.data ``=``=` `key:` `            ``incl ``=` `False` `        ``else``:` `            ``incl ``=` `True` `        `  `        ``sum` `=` `find_sum(root.left, key, ` `                       ``sum``, incl);` `        ``sum` `=` `find_sum(root.right, key, ` `                       ``sum``, incl);        ` `    ``return` `sum`          `# Driver code        ` `if` `__name__ ``=``=` `"__main__"``:` `    `  `    ``root ``=` `getNode(``15``);` `    ``root.left ``=` `getNode(``13``);` `    ``root.left.left ``=` `getNode(``12``);` `    ``root.left.left.left ``=` `getNode(``11``);` `    ``root.left.right ``=` `getNode(``14``);` `    ``root.right ``=` `getNode(``20``);` `    ``root.right.left ``=` `getNode(``18``);` `    ``root.right.right ``=` `getNode(``24``);` `    ``root.right.right.left ``=` `getNode(``23``);` `    ``root.right.right.right ``=` `getNode(``25``);` `    `  `    ``key ``=` `20``;` `    ``sum` `=` `0``;` `    ``sum` `=` `find_sum(root, key, ` `                   ``sum``, ``True``);` `    ``print``(``sum``)`   `# This code is contributed by Rutvik_56`

## C#

 `// C# program to find total sum ` `// except a given Node in BT ` `using` `System;`   `public` `class` `Node` `{` `    ``public` `int` `data;` `    ``public` `Node left, right;` `    `  `    ``// insertion of Node in Tree` `    ``public` `Node(``int` `key)` `    ``{` `        ``data = key;` `        ``left = right = ``null``;` `    ``}` `}` `public` `class` `GFG` `{` `public` `class` `cal` `{` `    ``public` `int` `sum = 0;` `    ``}` `    `  `    ``// sum of all element except those` `    ``// which are adjacent to key Node` `    ``public` `static` `void` `find_sum(Node root, ` `                    ``int` `key, cal r, ``bool` `incl)` `    ``{` `        ``if``(root != ``null``)` `        ``{` `            ``if``(incl == ``true``)` `            ``{` `                ``r.sum += root.data;` `                ``if``((root.left != ``null``) && ` `                    ``(root.left.data == key))` `                ``{` `                    ``r.sum -= root.data;` `                ``}` `                ``else` `                ``if``((root.right != ``null``) &&` `                    ``(root.right.data == key))` `                ``{` `                    ``r.sum -= root.data;` `                ``}` `                `  `            ``}` `            `  `            ``if``(root.data == key)` `                ``incl = ``false``;` `            ``else` `                ``incl = ``true``;` `                `  `        ``find_sum(root.left, key, r, incl);` `        ``find_sum(root.right, key, r, incl);` `        ``}` `    ``}` `    `  `// Driver code` `public` `static` `void` `Main (String[] args) ` `{` `        ``Node root = ``new` `Node(15);` `        ``root.left = ``new` `Node(13);` `        ``root.left.left = ``new` `Node(12);` `        ``root.left.left.left = ``new` `Node(11);` `        ``root.left.right = ``new` `Node(14);` `        ``root.right = ``new` `Node(20);` `        ``root.right.left = ``new` `Node(18);` `        ``root.right.right = ``new` `Node(24);` `        ``root.right.right.right = ``new` `Node(25);` `        ``root.right.right.left = ``new` `Node(23);` `        ``int` `key = 20;` `        ``cal obj = ``new` `cal();` `        ``find_sum(root, key, obj, ``true``);` `        ``Console.Write(obj.sum);` `    ``}` `}`   `// This code is contributed Rajput-Ji `

## Javascript

 ``

Output

`118 `

Time Complexity: O(n) where n is the number of nodes in BT.

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