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std::is_literal_type in C++ with Examples

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The std::is_literal_type template of C++ STL is present in the <type_traits> header file. The std::is_literal_type template of C++ STL is used to check whether the T is literal type or not. It return the boolean value true if T is literal type, otherwise return false.

Header File:



template< class T >
struct is_literal_type;



Parameter: The template std::is_literal_type accepts a single parameter T(Trait class) to check whether T is literal type or not.

Return Value: The template std::is_literal_type returns a boolean variable as shown below:

  • True: If the type T is a literal type.
  • False: If the type T is not a literal type.

Below is the program to demonstrate std::is_literal_type: in C/C++:


// C++ program to illustrate
// std::is_literal_type
#include <bits/stdc++.h>
#include <type_traits>
using namespace std;
// Declare Classes
class X {
class Y {
    // Destructor
    ~Y() {}
// Declare structures
struct A {
    int m;
struct B {
    virtual ~B();
// Driver Code
int main()
    cout << boolalpha;
    // Check if int is literal type?
    cout << "int: "
         << is_literal_type<int>::value
         << endl;
    // Check if class X is literal type?
    cout << "class X: "
         << is_literal_type<X>::value
         << endl;
    // Check if class Y is literal type?
    cout << "class Y: "
         << is_literal_type<Y>::value
         << endl;
    // Check if int* is literal type?
    cout << "int*: "
         << is_literal_type<int*>::value
         << endl;
    // Check if struct A is literal type?
    cout << "struct A: "
         << is_literal_type<A>::value
         << endl;
    // Check if struct B is literal type?
    cout << "struct B: "
         << is_literal_type<B>::value
         << endl;
    return 0;


int: true
class X: true
class Y: false
int*: true
struct A: true
struct B: false


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Last Updated : 12 Jun, 2020
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