# Spherical Cap Volume Formula

A spherical cap is a part of a sphere that is obtained by cutting it with a plane. It is the section of a sphere that extends above the sphere’s plane and formed when a plane cuts off a part of a sphere. The base area, height, and sphere radius are all the values that are required to calculate the volume of a spherical cap.

**Formula**

V = (1/3)π(3R – h)h^{2}where,

R is the radius of sphere,

h is the height of spherical cap,

π is a constant with a value of 22/7.

Using Pythagoras theorem, we can say that (R – h)

^{2}+ a^{2}= R^{2}. So, the formula can also be written as,

V = (1/6)πh(3a^{2}+ h^{2})Here, a denotes the radius of spherical cap.

**Sample Problems**

**Problem 1. Find the volume of the spherical cap if the radius of the sphere is 7 m and the height of the cap is 10 m.**

**Solution:**

We have, r = 7 and h = 10.

Using the formula we have,

V = (1/3)π(3R – h)h

^{2}= (1/3) (22/7) (3(7) – 10) (10

^{2})= (1/3) (22/7) (11) (100)

= 1152 cu. m

**Problem 2. Find the volume of the spherical cap if the radius of the sphere is 5 m and the height of the cap is 5 m.**

**Solution:**

We have, r = 5 and h = 5.

Using the formula we have,

V = (1/3)π(3R – h)h

^{2}= (1/3) (22/7) (3(5) – 5) (5

^{2})= (1/3) (22/7) (10) (25)

= 261.8 cu. m

**Problem 3. Find the volume of the spherical cap if the radius of the sphere is 7.5 m and the height of the cap is 12 m.**

**Solution:**

We have, r = 7.5 and h = 12.

Using the formula we have,

V = (1/3)π(3R – h)h

^{2}= (1/3) (22/7) (3(7.5) – 5) (12

^{2})= (1/3) (22/7) (17.5) (144)

= 1583.4 cu. m

**Problem 4. Find the radius of the sphere if the height and volume of the cap are 15 m and 2120.6 cu. m respectively.**

**Solution:**

We have, V = 2120.6 and h = 15.

Using the formula we have,

V = (1/3)π(3R – h)h

^{2}=> 2120.6 = (1/3) (22/7) (3R – 15) (15

^{2})=> 2120.6 = (1/3) (22/7) (3R – 15) (225)

=> 3R – 15 = 9

=> 3R = 24

=> R = 8 m

**Problem 5. Find the radius of the spherical cap if the height and volume of the cap are 6.5 m and 1305.2 cu. m respectively.**

**Solution:**

We have, V = 1305.2 and h = 6.5.

Using the formula we have,

V = (1/3)π(3R – h)h

^{2}=> 1305.2 = (1/3) (22/7) (3R – 15) (6.5)

^{2}=> 1305.2 = (1/3) (22/7) (3R – 6.5) (42.25)

=> 3R – 6.5 = 29.5

=> 3R = 36

=> R = 12 m

Now using the formula (R – h)

^{2}+ a^{2}= R^{2}, we havea

^{2}= R^{2}– (R – h)^{2}a

^{2}= 12^{2 }– (12 – 6.5)^{2}a

^{2}= 144 – 30.25a

^{2}= 113.75a = 10.67 m

**Problem 6. Find the volume of a spherical cap if its radius is 7 m and height is 14 m.**

**Solution:**

We have, a = 7 and h = 14.

Using the formula we have,

V = (1/6)πh(3a

^{2}+ h^{2})= (1/6) (22/7) (14) (3 (7)

^{2}+ 14^{2})= (1/6) (22/7) (14) (343)

= 2514.3 cu. m

**Problem 7. Find the volume of a spherical cap if its radius is 4.21 m and height is 9.54 m.**

**Solution:**

We have, a = 4.21 and h = 9.54.

Using the formula we have,

V = (1/6)πh(3a

^{2}+ h^{2})= (1/6) (22/7) (9.54) (3 (4.21)

^{2}+ 9.54^{2})= (1/6) (22/7) (14) (144.183)

= 720.2 cu. m

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