Sort an almost sorted array where only two elements are swapped
Given an almost sorted array where only two elements are swapped, how to sort the array efficiently?
Examples :
Input: arr[] = {10, 20, 60, 40, 50, 30} // 30 and 60 are swapped Output: arr[] = {10, 20, 30, 40, 50, 60} Input: arr[] = {10, 20, 40, 30, 50, 60} // 30 and 40 are swapped Output: arr[] = {10, 20, 30, 40, 50, 60} Input: arr[] = {1, 5, 3} // 3 and 5 are swapped Output: arr[] = {1, 3, 5}
Expected time complexity is O(n) and only one swap operation to fix the array.
The idea is to traverse from rightmost side and find the first out of order element (element which is smaller than previous element). Once first element is found, find the other out of order element by traversing the array toward left side.
Below is implementation of above idea.
C++
// C++ program to sort using one swap #include<iostream> #include<algorithm> using namespace std; // This function sorts an array that can be sorted // by single swap void sortByOneSwap( int arr[], int n) { // Traverse the given array from rightmost side for ( int i = n-1; i > 0; i--) { // Check if arr[i] is not in order if (arr[i] < arr[i-1]) { // Find the other element to be // swapped with arr[i] int j = i-1; while (j>=0 && arr[i] < arr[j]) j--; // Swap the pair swap(arr[i], arr[j+1]); break ; } } } // A utility function to print an array of size n void printArray( int arr[], int n) { int i; for (i=0; i < n; i++) cout << arr[i] << " " ; cout << endl; } /* Driver program to test insertion sort */ int main() { int arr[] = {10, 30, 20, 40, 50, 60, 70}; int n = sizeof (arr)/ sizeof (arr[0]); cout << "Given array is \n" ; printArray(arr, n); sortByOneSwap(arr, n); cout << "Sorted array is \n" ; printArray(arr, n); return 0; } |
Java
// Java program to // sort using one swap import java.io.*; class GFG { // This function sorts an array // that can be sorted by single swap static void sortByOneSwap( int arr[], int n) { // Traverse the given array // from rightmost side for ( int i = n - 1 ; i > 0 ; i--) { // Check if arr[i] // is not in order if (arr[i] < arr[i - 1 ]) { // Find the other element // to be swapped with arr[i] int j = i - 1 ; while (j >= 0 && arr[i] < arr[j]) j--; // Swap the pair int temp = arr[i]; arr[i] = arr[j + 1 ]; arr[j + 1 ] = temp; break ; } } } // A utility function to // print an array of size n static void printArray( int arr[], int n) { int i; for (i = 0 ; i < n; i++) System.out.print(arr[i] + " " ); System.out.println(); } // Driver Code public static void main(String[] args) { int arr[] = { 10 , 30 , 20 , 40 , 50 , 60 , 70 }; int n = arr.length; System.out.println( "Given array is " ); printArray(arr, n); sortByOneSwap(arr, n); System.out.println( "Sorted array is " ); printArray(arr, n); } } // This code is contributed by anuj_67. |
Python3
# Python program to # sort using one swap # This function sorts an array # that can be sorted by single swap def sortByOneSwap(arr, n): # Traverse the given array # from rightmost side for i in range (n - 1 , 0 , - 1 ): # Check if arr[i] # is not in order if (arr[i] < arr[i - 1 ]): # Find the other element # to be swapped with arr[i] j = i - 1 ; while (j > = 0 and arr[i] < arr[j]): j - = 1 ; # Swap the pair temp = arr[i]; arr[i] = arr[j + 1 ]; arr[j + 1 ] = temp; break ; # A utility function to # print an array of size n def printArray(arr, n): for i in range (n): print (arr[i], end = " " ); print (); # Driver Code if __name__ = = '__main__' : arr = [ 10 , 30 , 20 , 40 , 50 , 60 , 70 ]; n = len (arr); print ( "Given array is " ); printArray(arr, n); sortByOneSwap(arr, n); print ( "Sorted array is " ); printArray(arr, n); # This code is contributed by gauravrajput1 |
C#
// C# program to sort using one swap using System; class GFG { // This function sorts an array // that can be sorted by single swap static void sortByOneSwap( int []arr, int n) { // Traverse the given array // from rightmost side for ( int i = n - 1; i > 0; i--) { // Check if arr[i] is not in order if (arr[i] < arr[i - 1]) { // Find the other element to be // swapped with arr[i] int j = i - 1; while (j >= 0 && arr[i] < arr[j]) j--; // Swap the pair int temp = arr[i]; arr[i] = arr[j + 1]; arr[j + 1] = temp; break ; } } } // A utility function to print an // array of size n static void printArray( int []arr, int n) { int i; for (i = 0; i < n; i++) Console.Write(arr[i] + " " ); Console.WriteLine(); } // Driver Code public static void Main() { int []arr = {10, 30, 20, 40, 50, 60, 70}; int n = arr.Length; Console.WriteLine( "Given array is " ); printArray(arr, n); sortByOneSwap(arr, n); Console.WriteLine( "Sorted array is " ); printArray(arr, n); } } // This code is contributed by 29AjayKumar |
PHP
<?php // PHP program to sort using one swap // This function sorts an array // that can be sorted by single swap function sortByOneSwap(& $arr , $n ) { // Traverse the given array // from rightmost side for ( $i = $n - 1; $i > 0; $i --) { // Check if arr[i] // is not in order if ( $arr [ $i ] < $arr [ $i - 1]) { // Find the other element // to be swapped with arr[i] $j = $i - 1; while ( $j >= 0 && $arr [ $i ] < $arr [ $j ]) $j --; // Swap the pair $temp = $arr [ $i ]; $arr [ $i ] = $arr [ $j + 1]; $arr [ $j + 1] = $temp ; break ; } } } // A utility function to // print an array of size n function printArray(& $arr , $n ) { for ( $i = 0; $i < $n ; $i ++) echo $arr [ $i ] . " " ; echo "\n" ; } // Driver Code $arr = array (10, 30, 20, 40, 50, 60, 70); $n = sizeof( $arr ); echo "Given array is " . "\n" ; printArray( $arr , $n ); sortByOneSwap( $arr , $n ); echo "Sorted array is " . "\n" ; printArray( $arr , $n ); // This code is contributed by Akanksha Rai |
Javascript
<script> // Javascript program to sort using one swap // This function sorts an array // that can be sorted by single swap function sortByOneSwap(arr, n) { // Traverse the given array // from rightmost side for (let i = n - 1; i > 0; i--) { // Check if arr[i] is not in order if (arr[i] < arr[i - 1]) { // Find the other element to be // swapped with arr[i] let j = i - 1; while (j >= 0 && arr[i] < arr[j]) j--; // Swap the pair let temp = arr[i]; arr[i] = arr[j + 1]; arr[j + 1] = temp; break ; } } } // A utility function to print an // array of size n function printArray(arr, n) { let i; for (i = 0; i < n; i++) document.write(arr[i] + " " ); document.write( "</br>" ); } let arr = [10, 30, 20, 40, 50, 60, 70]; let n = arr.length; document.write( "Given array is " + "</br>" ); printArray(arr, n); sortByOneSwap(arr, n); document.write( "Sorted array is " + "</br>" ); printArray(arr, n); // This code is contributed by divyeshrabadiya07. </script> |
Output :
Given array is 10 30 20 40 50 60 70 Sorted array is 10 20 30 40 50 60 70
Time Complexity: O(N), as we are using a loop to traverse the array.
Auxiliary Space: O(1), as we are not using extra space.
The above program works in O(n) time and swaps only one element.
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