Sort 3 Integers without using if condition or using only max() function

Given three inte­gers, print them in sorted order with­out using if condition.
Examples :

Input  : a = 3, b = 2, c = 9
Output : 2 3 9

Input  : a = 4, b = 1, c = 9
Output : 1 4 9

Approach :
1. Find the max­i­mum of a, b, c using max() function. 
3. Mul­ti­ply all inte­gers by –1. Again find Min­i­mum of –a, –b, –c using max() function. 
4. Add the Max and Min from above steps and sub­tract the sum from (a+b+c). It gives us mid­dle element.
It works for negative numbers also.

C++

// C++ program to print three numbers
// in sorted order using max function
#include<bits/stdc++.h>
using namespace std;

void printSorted(int a, int b, int c)
{
    // Find maximum element
    int get_max = max(a, max(b, c));

    // Find minimum element
    int get_min = -max(-a, max(-b, -c));

    int get_mid = (a + b + c)
                 - (get_max + get_min);

    cout << get_min << " " << get_mid
        << " " << get_max;
}

// Driver code
int main()
{
    int a = 4, b = 1, c = 9;
    printSorted(a, b, c);
    return 0;
}

Java

// Java program to print three numbers
// in sorted order using max function
class GFG
{

    static void printSorted(int a, int b, int c)
    {
        // Find maximum element
        int get_max = Math.max(a, Math.max(b, c));

        // Find minimum element
        int get_min = -Math.max(-a, Math.max(-b, -c));

        int get_mid = (a + b + c)
                      - (get_max + get_min);

        System.out.print(get_min + " " + get_mid
                                + " " + get_max);
    }

    // Driver code
    public static void main(String[] args)
    {

        int a = 4, b = 1, c = 9;

        printSorted(a, b, c);
    }
}

// This code is contributed by Anant Agarwal.

Python3

# Python3 program to print three numbers
# in sorted order using max function

def printSorted(a, b, c):

    # Find maximum element
    get_max = max(a, max(b, c))

    # Find minimum element
    get_min = -max(-a, max(-b, -c))

    get_mid = (a + b + c) - (get_max + get_min)

    print(get_min, " " , get_mid, " " , get_max)

# Driver Code
a, b, c = 4, 1, 9
printSorted(a, b, c)

# This code is contributed by Anant Agarwal.

C#

// C# program to print three numbers
// in sorted order using max function
using System;

class GFG {

    static void printSorted(int a, int b, int c)
    {
        // Find maximum element
        int get_max = Math.Max(a, Math.Max(b, c));

        // Find minimum element
        int get_min = -Math.Max(-a, Math.Max(-b, -c));

        int get_mid = (a + b + c) -
                      (get_max + get_min);

    Console.Write(get_min + " " + get_mid
                          + " " + get_max);
    }

    // Driver code
    public static void Main()
    {
        int a = 4, b = 1, c = 9;

        printSorted(a, b, c);
    }
}

// This code is contributed by nitin mittal.

PHP

<?php
// PHP program to print three numbers
// in sorted order using max function

function printSorted($a, $b, $c)
{

    // Find maximum element
    $get_max = max($a, max($b, $c));

    // Find minimum element
    $get_min = -max(-$a, max(-$b, -$c));

    $get_mid = ($a + $b + $c) -
               ($get_max + $get_min);

    echo $get_min , " " , $get_mid, " " , $get_max;
}

    // Driver Code
    $a = 4;
    $b = 1;
    $c = 9;
    printSorted($a, $b,$c);

// This code is contributed by nitin mittal.
?>

Javascript

<script>

// JavaScript program for the above approach
function printSorted(a, b, c)
    {

        // Find maximum element
        let get_max = Math.max(a, Math.max(b, c));

        // Find minimum element
        let get_min = -Math.max(-a, Math.max(-b, -c));

        let get_mid = (a + b + c)
                      - (get_max + get_min);

        document.write(get_min + " " + get_mid
                                + " " + get_max);
    }

// Driver Code

     let a = 4, b = 1, c = 9;
     printSorted(a, b, c);

// This code is contributed by splevel62.
</script>

Output: 

 1 4 9

Time Complexity: O(1)
Auxiliary Space: O(1)

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