# Search a string in Matrix Using Split function in Java

• Difficulty Level : Easy
• Last Updated : 08 Sep, 2022

Given a string str and a matrix mat[][] of lowercase English alphabets, the task is to find whether the string str appears in the matrix (either row-wise or column-wise).

Examples:

```Input: str = "GFG"
mat[][] = {{'G', 'E', 'E', 'K', 'S'},
{'F', 'O', 'R', 'A', 'N'},
{'G', 'E', 'E', 'K', 'S'}}
Output: Yes
GFG is present in the first column.

Input: str = "SSS"
mat[][] = {{'G', 'E', 'E', 'K', 'S'},
{'F', 'O', 'R', 'A', 'N'},
{'G', 'E', 'E', 'K', 'S'}}
Output: No```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

If the search string is present in any row of the matrix the following results will be produced by the split function:

1. If the string occupies the whole row then the split function will return an array of length zero.
2. If the string is present in between characters then the array length will be greater than one.
3. If the array length is one then three possible cases can be there-
• The string occurs in first half.
• The string occurs in second half.
• The string is not present in that row.
4. To search the string column wise transpose the matrix and repeat step one.
5. Print Yes if the string is found else print No.

Below is the implementation of the above approach:

## Java

 `// Java program to search a string in` `// the matrix using split function` `import` `java.util.*;` `public` `class` `GFG {`   `    ``// Function to check the occurrence of string in the matrix` `    ``public` `static` `int` `check(String[] matrix, String string)` `    ``{` `        ``// Looping the contents in the matrix` `        ``for` `(String input : matrix) {`   `            ``// using split operator` `            ``String[] value = input.split(string);`   `            ``if` `(value.length >= ``2` `|| value.length == ``0``) {` `                ``return` `1``;` `            ``}` `            ``else` `if` `(value.length == ``1` `                    ``&& input.length() != value[``0``].length()) {` `                ``return` `1``;` `            ``}` `        ``}` `        ``return` `0``;` `    ``}`   `    ``// Function to transpose the given matrix` `    ``public` `static` `String[] vertical(String[] matrix)` `    ``{` `        ``String[] vertical_value = ``new` `String[matrix[``0``].length()];` `        ``for` `(``int` `i = ``0``; i < matrix[``0``].length(); i++) {` `            ``String temp = ``""``;` `            ``for` `(``int` `j = ``0``; j < matrix.length; j++)` `                ``temp += matrix[j].charAt(i);` `            ``vertical_value[i] = temp;` `        ``}`   `        ``// returning the transposed matrix` `        ``return` `vertical_value;` `    ``}`   `    ``// Driver code` `    ``public` `static` `void` `main(String[] args)` `    ``{`   `        ``// Input matrix of characters` `        ``String[] matrix = { ``"GEEKS"``, ``"FORAN"``, ``"GEEKS"` `};`   `        ``// element to be searched` `        ``String search = ``"GFG"``;`   `        ``// Transpose of the matrix` `        ``String[] verticalMatrix = vertical(matrix);`   `        ``// Searching process` `        ``int` `horizontal_search = check(matrix, search);` `        ``int` `vertical_search = check(verticalMatrix, search);`   `        ``// If found` `        ``if` `(horizontal_search == ``1` `|| vertical_search == ``1``)` `            ``System.out.println(``"Yes"``);` `        ``else` `            ``System.out.println(``"No"``);` `    ``}` `}`

Output

```Yes
```

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