QA – Placement Quizzes | Trigonometry & Height and Distances | Question 7
From a point A on a level ground, the angle of elevation of the top of a tower is 30 degrees. If the tower is 100 m high, the distance of point A from the foot of the tower is:
Let QR be the tower. Then, QR = 100 m and angle QAR = 30 degrees. We know, cot 30° = √3 = AQ/QR. Therefore, AQ = 100*√3 = 173 m.
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