QA – Placement Quizzes | Mixtures and Alligation | Question 9

A vessel full of orange juice contains 40% orange pulp. A part of juice is replaced by another juice containing 19% orange pulp and now the percentage of orange pulp is found to be 26%. What quantity of juice is replaced?
(A) 3:2
(B) 5:4
(C) 4:5
(D) 2:3


Answer: (D)

Explanation: Concentration of orange pulp in 1^st vessel = 40%
Concentration of orange pulp in 2^nd vessel = 19%
After the mixing, Concentration of orange pulp in the mixture = 26%
By rule of alligation,

Concentration of orange pulp in 1st vessel	Concentration of orange pulp in 2nd vessel
40%	19%
26%
26-19=7	40-26=14

Hence ratio of 1^st and 2^nd quantities = 7 : 14 = 1 : 2

i.e., 2/(1+2)=2/3 part of the juice is replaced.

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