QA – Placement Quizzes | Mixtures and Alligation | Question 7
Two solutions S1 and S2 contain whisky and soda in the ratio 2 : 5 and 6 : 7 respectively. In what ratio these solutions be mixed to get a new solution S3, containing whisky and soda in the ratio 5 : 8 ?
Let the amount taken from S1 be 7x And amount taken from S2 be 13y (2x + 6y)/(5x + 7y) = 5/8 16x + 48y = 25x + 35y 9x = 13y x/y = 13/9 Actual ratios of amounts = 7x/13y = (7/13) * (13/9) = 7/9
Please refer Mixture and Alligation for direct formula.
Quiz of this Question
My Personal Notes arrow_drop_up
Please Login to comment...