QA – Placement Quizzes | Mixtures and Alligation | Question 5
A sikanji vendor has two drums of sikanji. The first contains 75% of sikanji. The second contains 50% sikanji. How much sikanji should he mix from each of the drum so as to get twelve litres of sikanji such that the ratio of sikanji to soda is 5 : 3?
Explanation: Let x litrs from 1st drum and 12-x litrs from 2nd drum are mixed
sikanji from 1st drum = .75x
soda from 1st drum = .25x
sikanji from 2nd drum = .5(12-x)
soda from 2nd drum = .5(12-x)
total sikanji = .25x+6
total soda = .25x+.5(12-x) = 6-.25x
ratio = (.25x+6)/(6-.25x) = 5/3
.75x+18 = 30-1.25x
x=6 sikanji and 6 soda
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