QA – Placement Quizzes | Algebra | Question 14
If a total of 324 coins of 20 paise and 25 paise make a sum of Rs 71. Then find the number of 25-paise coins.
Let the number of 20-paise coins be x and the number of 25-paise coins be y. Then, x + y = 324 (equation 1) And, x/5 + y/4 = 71 4x + 5y = 71*20 (Multiplying by 20 on both sides) Substituting the value of x from equation 1, we get 4(324-y) + 5y = 71*20.
1296 – 4y + 5y = 1420
Therefore, y = 124.
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