QA – Placement Quizzes | Algebra | Question 13
A zoo has some peacocks and some horses. If the number of heads be 48 and the number of feet be 140, then the number of peacocks will be:
Let there be x peacocks and y horses. Then, x + y = 48 (equation 1) and 2x + 4y = 140 x + 2y = 70 Substituting the value of x from equation 1, we get 48-y + 2y = 70 y = 22 Then, x = 48 – 22 = 26.
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