Open in App
Not now

# Python – Value limits to keys in Dictionaries List

• Last Updated : 02 Dec, 2020

Given a Dictionaries list, write a Python program to assign limits to each key in dictionary list.( each having all keys ).

Examples:

Input : test_list = [{“gfg” : 4, “is” : 7, “best” : 10}, {“gfg” : 2, “is” : 5, “best” : 9}, {“gfg” : 1, “is” : 2, “best” : 6}]
Output : {‘gfg’: [1, 4], ‘is’: [2, 7], ‘best’: [6, 10]}
Explanation : gfg has min. value to be 1 and maximum to be 4.

Input : test_list = [{“gfg” : 4, “best” : 10}, {“gfg” : 2, “best” : 9}, {“gfg” : 1, “best” : 6}]
Output : {‘gfg’: [1, 4], ‘best’: [6, 10]}
Explanation : best has min. value to be 6 and maximum to be 10.

Method #1 : Using max() + min() + loop + keys()

In this, we perform task of getting all keys using keys(), and min and max values for limits are computed using min() and max(). The iteration of all the dictionaries is carried out using loop.

## Python3

 `# Python3 code to demonstrate working of ` `# Value limits to keys in Dictionaries List ` `# Using max() + min() + loop + keys() ` ` `  `# initializing Matrix ` `test_list ``=` `[{``"gfg"``: ``4``, ``"is"``: ``7``, ``"best"``: ``10``}, ` `             ``{``"gfg"``: ``2``, ``"is"``: ``5``, ``"best"``: ``9``}, ` `             ``{``"gfg"``: ``1``, ``"is"``: ``2``, ``"best"``: ``6``}] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `res ``=` `dict``() ` ` `  `# extraction of all keys ` `keys ``=` `list``(test_list[``0``].keys()) ` ` `  `for` `key ``in` `keys: ` ` `  `    ``# assigning ranges to each key ` `    ``res[key] ``=` `[``min``(sub[key] ``for` `sub ``in` `test_list), ``max``(sub[key] ` `                                                        ``for` `sub ``in` `test_list)] ` ` `  `# printing result ` `print``(``"Keys Ranges : "` `+` `str``(res)) `

Output:

The original list is : [{‘gfg’: 4, ‘is’: 7, ‘best’: 10}, {‘gfg’: 2, ‘is’: 5, ‘best’: 9}, {‘gfg’: 1, ‘is’: 2, ‘best’: 6}]
Keys Ranges : {‘gfg’: [1, 4], ‘is’: [2, 7], ‘best’: [6, 10]}

Method #2 : Using dictionary comprehension + min() + max() + keys()

In this, we perform task of iteration using one liner dictionary comprehension, just similar method as above method but a shorthand.

## Python3

 `# Python3 code to demonstrate working of ` `# Value limits to keys in Dictionaries List ` `# Using list comprehension + min() + max() + keys() ` ` `  `# initializing Matrix ` `test_list ``=` `[{``"gfg"``: ``4``, ``"is"``: ``7``, ``"best"``: ``10``}, ` `             ``{``"gfg"``: ``2``, ``"is"``: ``5``, ``"best"``: ``9``}, ` `             ``{``"gfg"``: ``1``, ``"is"``: ``2``, ``"best"``: ``6``}] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# extraction of all keys ` `keys ``=` `list``(test_list[``0``].keys()) ` ` `  `# Dictionary comprehension used as one liner to perform task ` `res ``=` `{key: [``min``(sub[key] ``for` `sub ``in` `test_list), ``max``(sub[key] ` `                                                     ``for` `sub ``in` `test_list)] ``for` `key ``in` `keys} ` ` `  `# printing result ` `print``(``"Keys Ranges : "` `+` `str``(res)) `

Output:

The original list is : [{‘gfg’: 4, ‘is’: 7, ‘best’: 10}, {‘gfg’: 2, ‘is’: 5, ‘best’: 9}, {‘gfg’: 1, ‘is’: 2, ‘best’: 6}]
Keys Ranges : {‘gfg’: [1, 4], ‘is’: [2, 7], ‘best’: [6, 10]}

My Personal Notes arrow_drop_up
Related Articles