Python – Symmetric Difference of Dictionaries
Given two Dictionaries, the task is to write a Python program to get the symmetric difference.
Examples:
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Input : test_dict1 = {‘Gfg’ : 4, ‘is’ : 3, ‘best’ : 7, ‘for’ : 3, ‘geek’ : 4},
test_dict2 = {‘Gfg’ : 4, ‘is’ : 3, ‘good’ : 7, ‘for’ : 3, ‘all’ : 4}
Output : {‘all’: 4, ‘good’: 7, ‘best’: 7, ‘geek’: 4}
Explanation : all, good, best and geek are mutually unique keys.
Input : test_dict1 = {‘Gfg’ : 4, ‘is’ : 3, ‘good’ : 7, ‘for’ : 3, ‘geek’ : 4},
test_dict2 = {‘Gfg’ : 4, ‘is’ : 3, ‘good’ : 7, ‘for’ : 3, ‘all’ : 4}
Output : {‘all’: 4, ‘geek’: 4}
Explanation : all, geek are mutually unique keys.
Method #1 : Using ^ operator + keys() + dictionary comprehension
In this, We extract all the keys using keys(), and get symmetric difference of all the keys using ^ operator. The required dictionary is compiled using dictionary comprehension.
Python3
# Python3 code to demonstrate working of # Symmetric Difference of Dictionaries # Using ^ operator + keys() + dictionary comprehension # initializing dictionaries test_dict1 = {'Gfg': 4, 'is': 3, 'best': 7, 'for': 3, 'geek': 4} test_dict2 = {'Gfg': 4, 'is': 3, 'good': 7, 'for': 3, 'all': 4} # printing original dictionaries print("The original dictionary 1 is : " + str(test_dict1)) print("The original dictionary 2 is : " + str(test_dict2)) # getting symmetric difference using ^ operation res = {key: test_dict1[key] if key in test_dict1 else test_dict2[key] for key in test_dict1.keys() ^ test_dict2.keys()} # printing result print("The symmetric difference : " + str(res)) |
Output:
The original dictionary 1 is : {‘Gfg’: 4, ‘is’: 3, ‘best’: 7, ‘for’: 3, ‘geek’: 4}
The original dictionary 2 is : {‘Gfg’: 4, ‘is’: 3, ‘good’: 7, ‘for’: 3, ‘all’: 4}
The symmetric difference : {‘geek’: 4, ‘best’: 7, ‘all’: 4, ‘good’: 7}
Method #2 : Using set.symmetric_difference() + keys()
In this, we perform task of getting uncommon elements using inbuilt function symmetric_difference().
Python3
# Python3 code to demonstrate working of # Symmetric Difference of Dictionaries # Using set.symmetric_difference() + keys() # initializing dictionaries test_dict1 = {'Gfg': 4, 'is': 3, 'best': 7, 'for': 3, 'geek': 4} test_dict2 = {'Gfg': 4, 'is': 3, 'good': 7, 'for': 3, 'all': 4} # printing original dictionaries print("The original dictionary 1 is : " + str(test_dict1)) print("The original dictionary 2 is : " + str(test_dict2)) # computing sym. difference using set inbuilt function res = {key: test_dict1[key] if key in test_dict1 else test_dict2[key] for key in set(test_dict1.keys()).symmetric_difference(test_dict2.keys())} # printing result print("The symmetric difference : " + str(res)) |
Output:
The original dictionary 1 is : {‘Gfg’: 4, ‘is’: 3, ‘best’: 7, ‘for’: 3, ‘geek’: 4}
The original dictionary 2 is : {‘Gfg’: 4, ‘is’: 3, ‘good’: 7, ‘for’: 3, ‘all’: 4}
The symmetric difference : {‘good’: 7, ‘all’: 4, ‘geek’: 4, ‘best’: 7}
