# Python – Symmetric Difference of Dictionaries

• Last Updated : 24 Feb, 2021

Given two Dictionaries, the task is to write a Python program to get the symmetric difference.

Examples:

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Input : test_dict1 = {‘Gfg’ : 4, ‘is’ : 3, ‘best’ : 7, ‘for’ : 3, ‘geek’ : 4},

test_dict2 = {‘Gfg’ : 4, ‘is’ : 3, ‘good’ : 7, ‘for’ : 3, ‘all’ : 4}

Output : {‘all’: 4, ‘good’: 7, ‘best’: 7, ‘geek’: 4}

Explanation : all, good, best and geek are mutually unique keys.

Input : test_dict1 = {‘Gfg’ : 4, ‘is’ : 3, ‘good’ : 7, ‘for’ : 3, ‘geek’ : 4},

test_dict2 = {‘Gfg’ : 4, ‘is’ : 3, ‘good’ : 7, ‘for’ : 3, ‘all’ : 4}

Output : {‘all’: 4, ‘geek’: 4}

Explanation : all, geek are mutually unique keys.

Method #1 : Using ^ operator + keys() + dictionary comprehension

In this, We extract all the keys using keys(), and get symmetric difference of all the keys using ^ operator. The required dictionary is compiled using dictionary comprehension.

## Python3

 `# Python3 code to demonstrate working of ` `# Symmetric Difference of Dictionaries ` `# Using ^ operator + keys() + dictionary comprehension ` ` `  `# initializing dictionaries ` `test_dict1 ``=` `{``'Gfg'``: ``4``, ``'is'``: ``3``, ``'best'``: ``7``, ``'for'``: ``3``, ``'geek'``: ``4``} ` `test_dict2 ``=` `{``'Gfg'``: ``4``, ``'is'``: ``3``, ``'good'``: ``7``, ``'for'``: ``3``, ``'all'``: ``4``} ` ` `  `# printing original dictionaries ` `print``(``"The original dictionary 1 is : "` `+` `str``(test_dict1)) ` `print``(``"The original dictionary 2 is : "` `+` `str``(test_dict2)) ` ` `  `# getting symmetric difference using ^ operation ` `res ``=` `{key: test_dict1[key] ``if` `key ``in` `test_dict1 ``else` `test_dict2[key] ` `       ``for` `key ``in` `test_dict1.keys() ^ test_dict2.keys()} ` ` `  `# printing result ` `print``(``"The symmetric difference : "` `+` `str``(res)) `

Output:

The original dictionary 1 is : {‘Gfg’: 4, ‘is’: 3, ‘best’: 7, ‘for’: 3, ‘geek’: 4}

The original dictionary 2 is : {‘Gfg’: 4, ‘is’: 3, ‘good’: 7, ‘for’: 3, ‘all’: 4}

The symmetric difference : {‘geek’: 4, ‘best’: 7, ‘all’: 4, ‘good’: 7}

Method #2 : Using set.symmetric_difference() + keys()

In this, we perform task of getting uncommon elements using inbuilt function symmetric_difference().

## Python3

 `# Python3 code to demonstrate working of ` `# Symmetric Difference of Dictionaries ` `# Using set.symmetric_difference() + keys() ` ` `  `# initializing dictionaries ` `test_dict1 ``=` `{``'Gfg'``: ``4``, ``'is'``: ``3``, ``'best'``: ``7``, ``'for'``: ``3``, ``'geek'``: ``4``} ` `test_dict2 ``=` `{``'Gfg'``: ``4``, ``'is'``: ``3``, ``'good'``: ``7``, ``'for'``: ``3``, ``'all'``: ``4``} ` ` `  `# printing original dictionaries ` `print``(``"The original dictionary 1 is : "` `+` `str``(test_dict1)) ` `print``(``"The original dictionary 2 is : "` `+` `str``(test_dict2)) ` ` `  `# computing sym. difference using set inbuilt function ` `res ``=` `{key: test_dict1[key] ``if` `key ``in` `test_dict1 ``else` `test_dict2[key] ``for` `key ``in` `       ``set``(test_dict1.keys()).symmetric_difference(test_dict2.keys())} ` ` `  `# printing result ` `print``(``"The symmetric difference : "` `+` `str``(res)) `

Output:

The original dictionary 1 is : {‘Gfg’: 4, ‘is’: 3, ‘best’: 7, ‘for’: 3, ‘geek’: 4}

The original dictionary 2 is : {‘Gfg’: 4, ‘is’: 3, ‘good’: 7, ‘for’: 3, ‘all’: 4}

The symmetric difference : {‘good’: 7, ‘all’: 4, ‘geek’: 4, ‘best’: 7}

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