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Python | Shuffle two lists with same order

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  • Last Updated : 22 Feb, 2022

Sometimes, while working with Python list, we can have a problem in which we need to perform shuffle operation in list. This task is easy and there are straightforward functionalities available in Python to perform this. But sometimes, we need to shuffle two lists so that their shuffle orders are consistent. Let’s discuss a way in which this task can be performed.
Method : Using zip() + shuffle() + * operator 
In this method, this task is performed in three steps. Firstly, the lists are zipped together using zip(). Next step is to perform shuffle using inbuilt shuffle() and last step is to unzip the lists to separate lists using * operator. 
 

Python3




# Python3 code to demonstrate working of
# Shuffle two lists with same order
# Using zip() + * operator + shuffle()
import random
 
# initializing lists
test_list1 = [6, 4, 8, 9, 10]
test_list2 = [1, 2, 3, 4, 5]
 
# printing lists
print(f"The original list 1 : {test_list1}")
print(f"The original list 2 : {test_list2}")
 
# Shuffle two lists with same order
# Using zip() + * operator + shuffle()
temp = list(zip(test_list1, test_list2))
random.shuffle(temp)
res1, res2 = zip(*temp)
# res1 and res2 come out as tuples, and so must be converted to lists.
res1, res2 = list(res1), list(res2)
 
# Printing result
print(f"List 1 after shuffle :  {res1}")
print(f"List 2 after shuffle :  {res2}")


Output : 

 
The original list 1 : [6, 4, 8, 9, 10]
The original list 2 : [1, 2, 3, 4, 5]
List 1 after shuffle : [6, 10, 4, 8, 9]
List 2 after shuffle : [1, 5, 2, 3, 4]

 

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