Python – Rotate dictionary by K

Given a dictionary perform its reordering by right rotating dictionary keys by K.

Examples:

Input : test_dict = {1:6, 8:1, 9:3, 10:8, 12:6, 4:9}, K = 2 
Output : {12: 6, 4: 9, 1: 6, 8: 1, 9: 3, 10: 8} 
Explanation : After right rotation ( cyclic ) by 2 elements, items are re-arranged.

Input : test_dict = {1:6, 8:1, 9:3, 10:8, 12:6, 4:9}, K = 1 
Output : {4: 9, 1: 6, 8: 1, 9: 3, 10: 8, 12: 6} 
Explanation : After right rotation ( cyclic ) by 1 element, items are re-arranged. 

Method #1 : Using list comprehension + items() + dictionary comprehension

In this, we perform task of conversion of dictionary to tuples list, and then perform list rotate, post that, result is again converted to dictionary to get resultant keys rotation.

Python3

# Python3 code to demonstrate working of
# Rotate dictionary by K
# Using list comprehension + items() + dictionary comprehension

# initializing dictionary
test_dict = {1: 6, 8: 1, 9: 3, 10: 8, 12: 6, 4: 9}

# printing original dictionary
print("The original dictionary is : " + str(test_dict))

# initializing K
K = 2

# converting to tuples list
test_dict = list(test_dict.items())

# performing rotate
res = [test_dict[(i - K) % len(test_dict)]
       for i, x in enumerate(test_dict)]

# reconverting to dictionary
res = {sub[0]: sub[1] for sub in res}

# printing result
print("The required result : " + str(res))

Output:

The original dictionary is : {1: 6, 8: 1, 9: 3, 10: 8, 12: 6, 4: 9}
The required result : {12: 6, 4: 9, 1: 6, 8: 1, 9: 3, 10: 8}

Method #2 : Using deque.rotate() + dictionary comprehension + items()

In this, we perform task of rotating using deque.rotate utility, rest all functionalities are performed in similar ways as per in above method.

Python3

# Python3 code to demonstrate working of
# Rotate dictionary by K
# Using deque.rotate() + dictionary comprehension + items()
from collections import deque

# initializing dictionary
test_dict = {1: 6, 8: 1, 9: 3, 10: 8, 12: 6, 4: 9}

# printing original dictionary
print("The original dictionary is : " + str(test_dict))

# initializing K
K = 2

# converting to tuples list
test_dict = list(test_dict.items())

# performing rotate
# using deque
test_dict = deque(test_dict)
test_dict.rotate(K)
test_dict = list(test_dict)

# reconverting to dictionary
res = {sub[0]: sub[1] for sub in test_dict}

# printing result
print("The required result : " + str(res))

Output:

The original dictionary is : {1: 6, 8: 1, 9: 3, 10: 8, 12: 6, 4: 9}
The required result : {12: 6, 4: 9, 1: 6, 8: 1, 9: 3, 10: 8}