 Open in App
Not now

# Python | Reverse Order Sort in String List

• Last Updated : 21 Mar, 2023

Sometimes, while working with Python, we can have a problem in which we need to perform the reverse sort operation in all the Strings that are present in a list. This problem can occur in general programming and web development. Let’s discuss certain ways in which this problem can be solved.

Method #1 : Using list comprehension + sorted() + join() + reverse This is one way in which this problem can be solved. In this, we use sorted() functionality to perform sort operation and join() is used to reconstruct the string list. The reverse logic is implemented by passing “reverse” as True parameter to sorted().

## Python3

 `# Python3 code to demonstrate working of ` `# Reverse Order Sort in String List` `# using list comprehension + sorted() + join() + reverse`   `# initialize list ` `test_list ``=` `[``'gfg'``, ``'is'``, ``'good'``] `   `# printing original list ` `print``("The original ``list` `: " ``+` `str``(test_list)) `   `# Reverse Order Sort in String List` `# using list comprehension + sorted() + join() + reverse` `res ``=` `[''.join(``sorted``(ele, reverse ``=` `True``)) ``for` `ele ``in` `test_list] `   `# printing result ` `print``("``List` `after string reverse sorting : " ``+` `str``(res)) `

Output :

```The original list : ['gfg', 'is', 'good']
List after string reverse sorting : ['ggf', 'si', 'oogd']```

Time complexity: O(n*nlogn), where n is the length of the test_list. The list comprehension + sorted() + join() + reverse takes O(n*nlogn) time
Auxiliary Space: O(n), extra space of size n is required

Method #2 : Using map() + sorted() + reverse + join() + lambda The combination of above method can also be used to perform this task. In this, we perform the functionality of traversal using map() and lambda rather than list comprehension. The reverse logic is implemented by passing “reverse” as True parameter to sorted().

## Python3

 `# Python3 code to demonstrate working of ` `# Reverse Order Sort in String List` `# using map() + sorted() + join() + lambda + reverse`   `# initialize list ` `test_list ``=` `[``'gfg'``, ``'is'``, ``'good'``] `   `# printing original list ` `print``("The original ``list` `: " ``+` `str``(test_list)) `   `# Reverse Order Sort in String List? + reverse` `# using map() + sorted() + join() + lambda ` `res ``=` `list``(``map``(``lambda` `ele: "".join(``sorted``(ele, reverse ``=` `True``)), test_list)) `   `# printing result ` `print``("``List` `after string reverse sorting : " ``+` `str``(res)) `

Output :

```The original list : ['gfg', 'is', 'good']
List after string reverse sorting : ['ggf', 'si', 'oogd']```

My Personal Notes arrow_drop_up
Related Articles