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Python – Resize Keys in dictionary

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  • Last Updated : 16 Nov, 2020
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Given Dictionary, resize keys to K by getting starting k elements from keys.

Input : test_dict = {“geeksforgeeks” :3, “best” :3, “coding” :4, “practice” :3}, K = 3 
Output : {‘gee’: 3, ‘bes’: 3, ‘cod’: 4, ‘pra’: 3} 
Explanation : Keys resized to have 3 elements.

Input : test_dict = {“geeksforgeeks” :3, “best” :3, “coding” :4, “practice” :3}, K = 4 
Output : {‘geek’: 3, ‘best’: 3, ‘codi’: 4, ‘prac’: 3} 
Explanation : Keys resized to have 4 elements. 

Method #1 : Using slicing + loop

In this, resizing is done using slicing of dictionary keys, loop is used to iterate for all the keys of dictionary. 

Python3




# Python3 code to demonstrate working of
# Resize Keys in dictionary
# Using slicing + loop
  
# initializing dictionary
test_dict = {"geeksforgeeks": 3, "best": 3, "coding": 4, "practice": 3}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# initializing K
K = 2
  
# reforming dictionary
res = dict()
for key in test_dict:
  
    # resizing to K prefix keys
    res[key[:K]] = test_dict[key]
  
# printing result
print("The required result : " + str(res))


Output:

The original dictionary is : {‘geeksforgeeks’: 3, ‘best’: 3, ‘coding’: 4, ‘practice’: 3}
The required result : {‘ge’: 3, ‘be’: 3, ‘co’: 4, ‘pr’: 3}

Method #2 : Using dictionary comprehension + slicing 

In this, we perform task of reforming dictionary in one liner using dictionary comprehension.

Python3




# Python3 code to demonstrate working of
# Resize Keys in dictionary
# Using dictionary comprehension + slicing
  
# initializing dictionary
test_dict = {"geeksforgeeks": 3, "best": 3, "coding": 4, "practice": 3}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# initializing K
K = 2
  
# reforming dictionary
res = {key[:K]: test_dict[key] for key in test_dict}
  
# printing result
print("The required result : " + str(res))


Output:

The original dictionary is : {‘geeksforgeeks’: 3, ‘best’: 3, ‘coding’: 4, ‘practice’: 3}
The required result : {‘ge’: 3, ‘be’: 3, ‘co’: 4, ‘pr’: 3}


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