Python Program to Swap dictionary item’s position

Given a Dictionary, the task is to write a python program to swap positions of dictionary items. The code given below takes two indices and swap values at those indices. 

Input : test_dict = {‘Gfg’ : 4, ‘is’ : 1, ‘best’ : 8, ‘for’ : 10, ‘geeks’ : 9}, i, j = 1, 3

Output : {‘Gfg’: 4, ‘for’: 10, ‘best’: 8, ‘is’: 1, ‘geeks’: 9}

Explanation : (for : 10) and (is : 1) swapped order.

Input : test_dict = {‘Gfg’ : 4, ‘is’ : 1, ‘best’ : 8, ‘for’ : 10, ‘geeks’ : 9}, i, j = 2, 3

Output : {‘Gfg’: 4, ‘is’: 1, ‘for’: 10, ‘best’: 8, ‘geeks’: 9}

Explanation : (for : 10) and (best : 8) swapped order.

Method : Using items() and dict()

This task is achieved in 3 steps:

• First dictionary is converted to equivalent key value pairs in form of tuples, 
• Next swap operation is performed in a Pythonic way. 
• At last, tuple list is converted back to dictionary, in its required format.

Example:

Python3

# initializing dictionary
test_dict = {'Gfg': 4, 'is': 1, 'best': 8, 'for': 10, 'geeks': 9}

# printing original dictionary
print("The original dictionary is : " + str(test_dict))

# initializing swap indices
i, j = 1, 3

# conversion to tuples
tups = list(test_dict.items())

# swapping by indices
tups[i], tups[j] = tups[j], tups[i]

# converting back
res = dict(tups)

# printing result
print("The swapped dictionary : " + str(res))

Output:

The original dictionary is : {‘Gfg’: 4, ‘is’: 1, ‘best’: 8, ‘for’: 10, ‘geeks’: 9}

The swapped dictionary : {‘Gfg’: 4, ‘for’: 10, ‘best’: 8, ‘is’: 1, ‘geeks’: 9}

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