Python program to sort Dictionary by Key Lengths

Given Dictionary, sort by its key lengths.

Input : test_dict = {“Gfg” : 4, “is” : 1, “best” : 0, “for” : 3, “geeks” : 3} 
Output : {‘is’: 1, ‘Gfg’: 4, ‘for’: 3, ‘best’: 0, ‘geeks’: 3} 
Explanation : 2 < 3 = 3 < 4 < 5, are sorted lengths in order.

Input : test_dict = {“Gfg” : 4, “for” : 3, “geeks” : 3} 
Output : {‘Gfg’: 4, ‘for’: 3, ‘geeks’: 3} 
Explanation : 3 = 3 < 5, are sorted lengths in order. 

Method #1 : Using len() + sort() + dictionary comprehension + items()

In this, we perform the task of sorting using sort(), items() is used to get tuple pair from the dictionary, len() gets the keys lengths. Then dictionary comprehension performs the task of converting back to dictionary.

Python3

# Python3 code to demonstrate working of
# Sort Dictionary by Key Lengths
# Using len() + sort() + dictionary comprehension + items()

def get_len(key):
    return len(key[0])

# initializing dictionary
test_dict = {"Gfg" : 4, "is" : 1, "best" : 0, "for" : 3, "geeks" : 3}

# printing original dictionary
print("The original dictionary is : " + str(test_dict))

# sorting using sort()
# external to render logic
test_dict_list = list(test_dict.items())
test_dict_list.sort(key = get_len)

# reordering to dictionary
res = {ele[0] : ele[1]  for ele in test_dict_list}

# printing result
print("The sorted dictionary : " + str(res))

Output:

The original dictionary is : {‘Gfg’: 4, ‘is’: 1, ‘best’: 0, ‘for’: 3, ‘geeks’: 3}
The sorted dictionary : {‘is’: 1, ‘Gfg’: 4, ‘for’: 3, ‘best’: 0, ‘geeks’: 3}

Method #2 : Using sorted() + lambda function + items() + dictionary comprehension

In this, we perform the task of sorting using sorted(), lambda function is used to provide the logic of getting key lengths.

Python3

# Python3 code to demonstrate working of
# Sort Dictionary by Key Lengths
# Using sorted() + lambda function + items() + dictionary comprehension

# initializing dictionary
test_dict = {"Gfg" : 4, "is" : 1, "best" : 0, "for" : 3, "geeks" : 3}

# printing original dictionary
print("The original dictionary is : " + str(test_dict))

# sorting using sorted()
# lambda fnc. to render logic
test_dict_list = sorted(list(test_dict.items()), key = lambda key : len(key[0]))

# reordering to dictionary
res = {ele[0] : ele[1]  for ele in test_dict_list}

# printing result
print("The sorted dictionary : " + str(res))

Output:

The original dictionary is : {‘Gfg’: 4, ‘is’: 1, ‘best’: 0, ‘for’: 3, ‘geeks’: 3}
The sorted dictionary : {‘is’: 1, ‘Gfg’: 4, ‘for’: 3, ‘best’: 0, ‘geeks’: 3}