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# Python Program to print sum of all key value pairs in a Dictionary

• Difficulty Level : Basic
• Last Updated : 18 Jan, 2023

Given a dictionary arr consisting of N items, where key and value are both of integer type, the task is to find the sum of all key value pairs in the dictionary.

Examples:

Input: arr = {1: 10, 2: 20, 3: 30}
Output: 11 22 33
Explanation:
Sum of key and value of the first item in the dictionary = 1 + 10 = 11.
Sum of key and value of the second item in the dictionary = 2 + 20 = 22.
Sum of key and value of the third item in the dictionary = 3 + 30 = 33.

Input: arr = {10 : -5, 5 : -10, 100 : -50}
Output: 5 -5 50

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Method 1:

Approach using dictionary traversal technique: The idea is to traverse through the keys of dictionary using for loop. Follow the steps below to solve the problem:

Below is the implementation of the above approach:

## Python3

 `# Python3 implementation of` `# the above approach`   `# Function to print the list containing` `# the sum of key and value pairs of` `# each item of a dictionary`     `def` `FindSum(arr):`   `    ``# Stores the list containing the` `    ``# sum of keys and values of each item` `    ``l ``=` `[]`   `    ``# Traverse the dictionary` `    ``for` `i ``in` `arr:`   `        ``l.append(i ``+` `arr[i])`   `    ``# Print the list l` `    ``print``(``*``l)`   `# Driver Code`     `arr ``=` `{``1``: ``10``, ``2``: ``20``, ``3``: ``30``}`   `FindSum(arr)`

Output

`11 22 33`

Time Complexity: O(N)
Auxiliary Space: O(N)

Method 2:

Approach using keys() Method: An alternate approach to solve the problem is to use keys() method. Follow the steps below to solve the problem:

Below is the implementation of the above approach:

## Python3

 `# Python3 implementation of the above approach`   `# Function to print the list` `# containing the sum of key and` `# value pairs from a dictionary`     `def` `FindSum(arr):`   `    ``# Stores the list containing the` `    ``# sum of keys and values of each item` `    ``l ``=` `[]`   `    ``# Traverse the list of keys of arr` `    ``for` `i ``in` `arr.keys():`   `        ``l.append(i ``+` `arr[i])`   `    ``# Print the list l` `    ``print``(``*``l)`   `# Driver Code`     `arr ``=` `{``1``: ``10``, ``2``: ``20``, ``3``: ``30``}`   `FindSum(arr)`

Output

`11 22 33`

Time Complexity: O(N)
Auxiliary Space: O(N)

Method 3 : Using keys(),values() and for loop

## Python3

 `# Python3 implementation of the above approach` `arr ``=` `{``1``: ``10``, ``2``: ``20``, ``3``: ``30``}` `x ``=` `list``(arr.keys())` `y ``=` `list``(arr.values())` `res ``=` `[]` `for` `i ``in` `range``(``0``, ``len``(x)):` `    ``res.append(x[i]``+``y[i])` `for` `i ``in` `res:` `    ``print``(i, end``=``" "``)`

Output

`11 22 33 `

Method 4: Using zip() and a list comprehension

This approach uses the python built-in function zip() to extract the keys and values of the dictionary and combines them in a tuple. Using a list comprehension, we add the key and value of each item in the dictionary. The final result is the sum of all key-value pairs in the dictionary. The time complexity of this approach is O(n) and the space complexity is O(n) as we are creating a new list to store the sum of each key-value pair.

## Python3

 `def` `find_sum(arr):` `    ``# Using zip to get the keys and values of the dictionary` `    ``keys, values ``=` `zip``(``*``arr.items())` `    ``# Using list comprehension to add the key and value of each item` `    ``return` `[k``+``v ``for` `k,v ``in` `zip``(keys, values)]`   `arr ``=` `{``1``: ``10``, ``2``: ``20``, ``3``: ``30``}` `print``(find_sum(arr))` `#This code is contributed by Edula Vinay Kumar Reddy`

Output

`[11, 22, 33]`

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