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# Python program to print odd numbers in a List

• Difficulty Level : Easy
• Last Updated : 19 Jan, 2023

Given a list of numbers, write a Python program to print all odd numbers in the given list.

Example:

```Input: list1 = [2, 7, 5, 64, 14]
Output: [7, 5]

Input: list2 = [12, 14, 95, 3, 73]
Output: [95, 3, 73]```

Using for loop : Iterate each element in the list using for loop and check if num % 2 != 0. If the condition satisfies, then only print the number.

## Python3

 `# Python program to print odd Numbers in a List`   `# list of numbers` `list1 ``=` `[``10``, ``21``, ``4``, ``45``, ``66``, ``93``]`   `# iterating each number in list` `for` `num ``in` `list1:`   `    ``# checking condition` `    ``if` `num ``%` `2` `!``=` `0``:` `       ``print``(num, end``=``" "``)`

Output

`21 45 93 `

Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.

## Python3

 `# Python program to print odd Numbers in a List`   `# list of numbers` `list1 ``=` `[``10``, ``21``, ``4``, ``45``, ``66``, ``93``]` `i ``=` `0`   `# using while loop` `while``(i < ``len``(list1)):`   `    ``# checking condition` `    ``if` `list1[i] ``%` `2` `!``=` `0``:` `        ``print``(list1[i], end``=``" "``)`   `    ``# increment i` `    ``i ``+``=` `1`

Output

`21 45 93 `

Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.

## Python3

 `# Python program to print odd Numbers in a List`   `# list of numbers` `list1 ``=` `[``10``, ``21``, ``4``, ``45``, ``66``, ``93``]`   `only_odd ``=` `[num ``for` `num ``in` `list1 ``if` `num ``%` `2` `=``=` `1``]`   `print``(only_odd)`

Output

`[21, 45, 93]`

Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.

Using lambda expressions :

## Python3

 `# Python program to print odd numbers in a List`   `# list of numbers ` `list1 ``=` `[``10``, ``21``, ``4``, ``45``, ``66``, ``93``, ``11``] `     `# we can also print odd no's using lambda exp. ` `odd_nos ``=` `list``(``filter``(``lambda` `x: (x ``%` `2` `!``=` `0``), list1))`   `print``(``"Odd numbers in the list:"``, odd_nos) `

Output

`Odd numbers in the list: [21, 45, 93, 11]`

Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.

## Python3

 `# Python program to print odd numbers in a List`   `lst ``=` `[``10``, ``21``, ``4``, ``45``, ``66``, ``93``, ``11``]` `for` `i ``in` `lst:` `    ``if` `i ``%` `2` `=``=` `0``:` `        ``pass` `    ``else``:` `        ``print``(i, end``=``" "``)`

Output

`21 45 93 11 `

Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.

## Python3

 `# Python program to print` `# odd numbers in a list using recursion`     `def` `oddnumbers(``list``, n``=``0``):` `    ``# base case` `    ``if` `n ``=``=` `len``(``list``):` `        ``exit()` `    ``if` `list``[n] ``%` `2` `!``=` `0``:` `        ``print``(``list``[n], end``=``" "``)` `    ``# calling function recursively` `    ``oddnumbers(``list``, n``+``1``)`     `list1 ``=` `[``10``, ``21``, ``4``, ``45``, ``66``, ``93``, ``11``]` `print``(``"odd numbers in the list:"``, end``=``" "``)` `oddnumbers(list1)`

Output

`odd numbers in the list: 21 45 93 11 `

Time Complexity: O(N)
Auxiliary Space: O(1), As the function is tail recursive no extra stack space is used.

## Python3

 `list1 ``=` `[``2``, ``7``, ``5``, ``64``, ``14``] ` `for` `a,i ``in` `enumerate``(list1):` `  ``if` `i``%``2``!``=``0``:` `    ``print``(i,end``=``" "``)`

Output

`7 5 `

Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.

## Python3

 `# Python program to print odd Numbers in a List` `import` `numpy as np` `# list of numbers` `list1 ``=` `np.array([``10``, ``21``, ``4``, ``45``, ``66``, ``93``])`     `only_odd ``=` `list1[list1 ``%` `2` `=``=` `1``]`   `print``(only_odd)`

Output:

`[21 45 93]`

### Method: Using bitwise & operator

We can also find the number odd or not using & operator. We iterate the through the list using for loop. If num & 1

==1.If the condition satisfies print element.

## Python3

 `#List of numbers` `list1 ``=` `[``9``,``5``,``4``,``7``,``2``]`   `for` `ele ``in` `list1:` `  ``if` `ele & ``1``: ``#Checking the element odd or not` `    ``print``(ele,end``=``" "``) `

Output

`9 5 7 `

### Method: Using bitwise | operator

We can also find the number odd or not using | operator. We iterate the through the list using for loop. If num | 1

==num. If the condition satisfies print element.

## Python3

 `#List of numbers` `list1 ``=` `[``9``,``5``,``4``,``7``,``2``]`   `for` `ele ``in` `list1:` `  ``if` `ele | ``1``=``=``ele: ``#Checking the element odd or not` `    ``print``(ele,end``=``" "``) `

Output

`9 5 7 `

### Time Complexity: O(N)Auxiliary Space: O(1), As constant extra space is used.

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