Python program to print odd numbers in a List
Given a list of numbers, write a Python program to print all odd numbers in the given list.
Example:
Input: list1 = [2, 7, 5, 64, 14] Output: [7, 5] Input: list2 = [12, 14, 95, 3, 73] Output: [95, 3, 73]
Using for loop : Iterate each element in the list using for loop and check if num % 2 != 0. If the condition satisfies, then only print the number.
Python3
# Python program to print odd Numbers in a List # list of numbers list1 = [ 10 , 21 , 4 , 45 , 66 , 93 ] # iterating each number in list for num in list1: # checking condition if num % 2 ! = 0 : print (num, end = " " ) |
21 45 93
Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.
Python3
# Python program to print odd Numbers in a List # list of numbers list1 = [ 10 , 21 , 4 , 45 , 66 , 93 ] i = 0 # using while loop while (i < len (list1)): # checking condition if list1[i] % 2 ! = 0 : print (list1[i], end = " " ) # increment i i + = 1 |
21 45 93
Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.
Python3
# Python program to print odd Numbers in a List # list of numbers list1 = [ 10 , 21 , 4 , 45 , 66 , 93 ] only_odd = [num for num in list1 if num % 2 = = 1 ] print (only_odd) |
[21, 45, 93]
Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.
Python3
# Python program to print odd numbers in a List # list of numbers list1 = [ 10 , 21 , 4 , 45 , 66 , 93 , 11 ] # we can also print odd no's using lambda exp. odd_nos = list ( filter ( lambda x: (x % 2 ! = 0 ), list1)) print ( "Odd numbers in the list:" , odd_nos) |
Odd numbers in the list: [21, 45, 93, 11]
Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.
Method: Using pass
Python3
# Python program to print odd numbers in a List lst = [ 10 , 21 , 4 , 45 , 66 , 93 , 11 ] for i in lst: if i % 2 = = 0 : pass else : print (i, end = " " ) |
21 45 93 11
Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.
Method: Using recursion
Python3
# Python program to print # odd numbers in a list using recursion def oddnumbers( list , n = 0 ): # base case if n = = len ( list ): exit() if list [n] % 2 ! = 0 : print ( list [n], end = " " ) # calling function recursively oddnumbers( list , n + 1 ) list1 = [ 10 , 21 , 4 , 45 , 66 , 93 , 11 ] print ( "odd numbers in the list:" , end = " " ) oddnumbers(list1) |
odd numbers in the list: 21 45 93 11
Time Complexity: O(N)
Auxiliary Space: O(1), As the function is tail recursive no extra stack space is used.
Method: Using enumerate function
Python3
list1 = [ 2 , 7 , 5 , 64 , 14 ] for a,i in enumerate (list1): if i % 2 ! = 0 : print (i,end = " " ) |
7 5
Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.
Method: Using numpy.array function
Python3
# Python program to print odd Numbers in a List import numpy as np # list of numbers list1 = np.array([ 10 , 21 , 4 , 45 , 66 , 93 ]) only_odd = list1[list1 % 2 = = 1 ] print (only_odd) |
Output:
[21 45 93]
Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.
Method: Using bitwise & operator
We can also find the number odd or not using & operator. We iterate the through the list using for loop. If num & 1
==1.If the condition satisfies print element.
Python3
#List of numbers list1 = [ 9 , 5 , 4 , 7 , 2 ] for ele in list1: if ele & 1 : #Checking the element odd or not print (ele,end = " " ) |
9 5 7
Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.
Method: Using bitwise | operator
We can also find the number odd or not using | operator. We iterate the through the list using for loop. If num | 1
==num. If the condition satisfies print element.
Python3
#List of numbers list1 = [ 9 , 5 , 4 , 7 , 2 ] for ele in list1: if ele | 1 = = ele: #Checking the element odd or not print (ele,end = " " ) |
9 5 7
Please Login to comment...