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# Python Program to Multiply Two Binary Numbers

• Last Updated : 23 Aug, 2021

Given two binary numbers, and the task is to write a Python program to multiply both numbers.

Example:

```firstnumber = 110
secondnumber = 10
Multiplication Result = 1100```

We can multiply two binary numbers in two ways using python, and these are:

1. Using bin() functions and
2. Without using pre-defined functions

## Method 1: Using bin Functions

Now, Let’s write a program by using Pre-Defined Functions:

## Python3

 `firstnumber ``=` `110` `secondnumber ``=` `10` ` `  `firstnumber ``=` `str``(firstnumber) ` `secondnumber ``=` `str``(secondnumber) ` ` `  `Multiplication ``=` `int``(firstnumber, ``2``) ``*` `int``(secondnumber, ``2``) ` `binaryMul ``=` `bin``(Multiplication) ` ` `  `print``(``"\nResult = "` `+` `binaryMul) `

Output:

`Result = 0b1100`

## Method 2: Without using Any Pre-Defined Function

We can also multiply any two Binary Numbers without using any pre-defined Function or by user-defined function.

## Python

 `def` `binaryProduct(binaryOne, binaryTwo): ` `    ``i ``=` `0` `    ``remainder ``=` `0` `    ``sum` `=` `[] ` `    ``binaryProd ``=` `0` ` `  `    ``# if firstBinary number or second Binary number is not ` `    ``# zero then calculate the product of two Binary numbers ` `    ``while` `binaryOne !``=` `0` `or` `binaryTwo !``=` `0``: ` `        ``sum``.insert(i, (((binaryOne ``%` `10``) ``+` `(binaryTwo ``%` `10``) ``+` `remainder) ``%` `2``)) ` `        ``remainder ``=` `int``(((binaryOne ``%` `10``) ``+` `(binaryTwo ``%` `10``) ``+` `remainder) ``/` `2``) ` `        ``binaryOne ``=` `int``(binaryOne``/``10``) ` `        ``binaryTwo ``=` `int``(binaryTwo``/``10``) ` `        ``i ``=` `i``+``1` ` `  `    ``# if remainder value is not equal to ` `    ``# zero then insert the digit to sum array ` `    ``if` `remainder !``=` `0``: ` `        ``sum``.insert(i, remainder) ` `        ``i ``=` `i``+``1` `    ``i ``=` `i``-``1` `    ``while` `i >``=` `0``: ` `        ``binaryProd ``=` `(binaryProd ``*` `10``) ``+` `sum``[i] ` `        ``i ``=` `i``-``1` `    ``return` `binaryProd ` ` `  ` `  `binaryMultiply ``=` `0` `factor ``=` `1` `firstBinary ``=` `110` ` `  `secondBinary ``=` `10` ` `  `# Now check if secondbinary number have any ` `# digit or not and continue multiplying ` `# each digit of the second binary number with ` `# first binary number till the last digit of ` `# second binary number ` `while` `secondBinary !``=` `0``: ` `    ``digit ``=` `secondBinary ``%` `10` `    ``if` `digit ``=``=` `1``: ` `        ``firstBinary ``=` `firstBinary ``*` `factor ` `        ``binaryMultiply ``=` `binaryProduct(firstBinary, binaryMultiply) ` `    ``else``: ` `        ``firstBinary ``=` `firstBinary ``*` `factor ` `    ``secondBinary ``=` `int``(secondBinary``/``10``) ` `    ``factor ``=` `10` `print``(``"\nMultiplication Result = "` `+` `str``(binaryMultiply)) `

Output:

`Multiplication Result = 1100`

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