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Python program to equal character frequencies

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  • Last Updated : 16 Aug, 2022
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Given a String, ensure it has equal character frequencies, if not, equate by adding required characters.

Input : test_str = ‘geeksforgeeks’ 
Output : geeksforgeeksggkkssfffooorrr 
Explanation : Maximum characters are 4 of ‘e’. Other character are appended of frequency 4 – (count of chars).

Input : test_str = ‘geksforgeeks’ 
Output : geeksforgeeksggksffoorr 
Explanation : Maximum characters are 3 of ‘e’. Other character are appended of frequency 3 – (count of chars).  

Method #1 : Using count() + max() + loop

In this, we get the frequency of the maximum occurring character, and then append each character to match the maximum character frequency.

Python3




# Python3 code to demonstrate working of
# Equal character frequencies
# Using max() + count() + loop
 
# initializing string
test_str = 'geeksforgeeks'
 
# printing original string
print("The original string is : " + str(test_str))
 
# getting maximum frequency character
max_freq = max([test_str.count(ele) for ele in test_str])
 
# equating frequencies
res = test_str
for chr in test_str:
     
    # if frequencies don't match max_freq
    if res.count(chr) != max_freq:
        res += chr * (max_freq - test_str.count(chr))
     
# printing result
print("Equal character frequency String : " + str(res))


Output

The original string is : geeksforgeeks
Equal character frequency String : geeksforgeeksggkkssfffooorrr

Time Complexity: O(n)
Auxiliary Space: O(n)

Method #2 : Using Counter() + loop 

Similar to the above, the difference being Counter() is used to get the maximum element count.

Python3




# Python3 code to demonstrate working of
# Equal character frequencies
# Using Counter() + loop
from collections import Counter
 
# initializing string
test_str = 'geeksforgeeks'
 
# printing original string
print("The original string is : " + str(test_str))
 
# getting maximum frequency character
# using Counter()
freq_dict = Counter(test_str)
max_freq = test_str.count(max(freq_dict, key = freq_dict.get))
 
# equating frequencies
res = test_str
for chr in test_str:
     
    # if frequencies don't match max_freq
    if res.count(chr) != max_freq:
        res += chr * (max_freq - test_str.count(chr))
     
# printing result
print("Equal character frequency String : " + str(res))


Output

The original string is : geeksforgeeks
Equal character frequency String : geeksforgeeksggkkssfffooorrr

Time Complexity: O(n)
Auxiliary Space: O(n)


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