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Python program to convert tuple into list by adding the given string after every element

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  • Last Updated : 26 Jul, 2022
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Given a Tuple. The task is to convert it to List by adding the given string after every element.

Examples:

Input : test_tup = (5, 6, 7), K = "Gfg" 
Output : [5, 'Gfg', 6, 'Gfg', 7, 'Gfg'] 
Explanation : Added "Gfg" as succeeding element.

Input : test_tup = (5, 6), K = "Gfg" 
Output : [5, 'Gfg', 6, 'Gfg'] 
Explanation : Added "Gfg" as succeeding element.

Method #1: Using list comprehension

In this, we construct a tuple of each element of tuple with a succeeding element and then run a nested loop to flatten each constructed tuple using list comprehension.

Python3




# Python3 code to demonstrate working of
# Convert tuple to List with succeeding element
# Using list comprehension
 
# initializing tuple
test_tup = (5, 6, 7, 4, 9)
 
# printing original tuple
print("The original tuple is : ", test_tup)
 
# initializing K
K = "Gfg"
 
# list comprehension for nested loop for flatten
res = [ele for sub in test_tup for ele in (sub, K)]
 
# printing result
print("Converted Tuple with K : ", res)


Output:

The original tuple is :  (5, 6, 7, 4, 9) 
Converted Tuple with K :  [5, ‘Gfg’, 6, ‘Gfg’, 7, ‘Gfg’, 4, ‘Gfg’, 9, ‘Gfg’]

Method #2 : Using chain.from_iterable() + list() + generator expression

This is similar to above method, difference is that nested loop is avoided by flattening using chain.from_iterable().

Python3




# Python3 code to demonstrate working of
# Convert tuple to List with succeeding element
# Using chain.from_iterable() + list() + generator expression
from itertools import chain
 
# initializing tuple
test_tup = (5, 6, 7, 4, 9)
 
# printing original tuple
print("The original tuple is : ", test_tup)
 
# initializing K
K = "Gfg"
 
# list comprehension for nested loop for flatten
res = list(chain.from_iterable((ele, K) for ele in test_tup))
 
# printing result
print("Converted Tuple with K : ", res)


Output:

The original tuple is :  (5, 6, 7, 4, 9) 
Converted Tuple with K :  [5, ‘Gfg’, 6, ‘Gfg’, 7, ‘Gfg’, 4, ‘Gfg’, 9, ‘Gfg’]

Method #3 : Using list(),map(),join(),split() methods

Python3




# Python3 code to demonstrate working of
# Convert tuple to List with succeeding element
 
# initializing tuple
test_tup = (5, 6, 7, 4, 9)
 
# printing original tuple
print("The original tuple is : ", test_tup)
 
# initializing K
K = "Gfg"
x = list(map(str, test_tup))
b = "*"+K+"*"
a = b.join(x)
c = a.split("*")
c.append(K)
res = []
for i in c:
    if(i != K):
        res.append(int(i))
    else:
        res.append(i)
# printing result
print("Converted Tuple with K : ", res)


Output :

The original tuple is :  (5, 6, 7, 4, 9) 
Converted Tuple with K :  [5, ‘Gfg’, 6, ‘Gfg’, 7, ‘Gfg’, 4, ‘Gfg’, 9, ‘Gfg’]


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