Python program for removing i-th character from a string
Given the string, we have to remove the ith indexed character from the string.
In any string, indexing always start from 0. Suppose we have a string geeks then its indexing will be as –
g e e k s 0 1 2 3 4
Examples :
Input : Geek i = 1 Output : Gek Input : Peter i = 4 Output : Pete
Approach 1 : From the given string, i-th indexed element has to be removed. So, Split the string into two halves, before indexed character and after indexed character. Return the merged string.
Below is the implementation of above approach :
# Python3 program for removing i-th # indexed character from a string # Removes character at index i def remove(string, i): # Characters before the i-th indexed # is stored in a variable a a = string[ : i] # Characters after the nth indexed # is stored in a variable b b = string[i + 1 : ] # Returning string after removing # nth indexed character. return a + b # Driver Code if __name__ = = '__main__' : string = "geeksFORgeeks" # Remove nth index element i = 5 # Print the new string print (remove(string, i)) |
Output:
geeksORgeeks
Approach 2 : The idea is to use string replace in Python
# Python3 program for removing i-th # indexed character from a string # Removes character at index i def remove(string, i): for j in range ( len (string)): if j = = i: string = string.replace(string[i], "", 1 ) return string # Driver Code if __name__ = = '__main__' : string = "geeksFORgeeks" # Remove nth index element i = 5 # Print the new string print (remove(string, i)) |
Output:
geeksORgeeks
