Python program for removing i-th character from a string

Given the string, we have to remove the i^th indexed character from the string.

In any string, indexing always start from 0. Suppose we have a string geeks then its indexing will be as –

g e e k s
0 1 2 3 4

Examples :

Input : Geek
        i = 1
Output : Gek 

Input : Peter 
        i = 4
Output : Pete

Approach 1 : From the given string, i-th indexed element has to be removed. So, Split the string into two halves, before indexed character and after indexed character. Return the merged string.

Below is the implementation of above approach :

# Python3 program for removing i-th
# indexed character from a string

# Removes character at index i
def remove(string, i):

    # Characters before the i-th indexed
    # is stored in a variable a
    a = string[ : i]

    # Characters after the nth indexed
    # is stored in a variable b
    b = string[i + 1: ]

    # Returning string after removing
    # nth indexed character.
    return a + b

# Driver Code
if __name__ == '__main__':

    string = "geeksFORgeeks"

    # Remove nth index element
    i = 5

    # Print the new string
    print(remove(string, i))

Output:

geeksORgeeks

Approach 2 : The idea is to use string replace in Python

# Python3 program for removing i-th
# indexed character from a string

# Removes character at index i
def remove(string, i):

    for j in range(len(string)):
        if j == i:
            string = string.replace(string[i], "", 1)
    return string

# Driver Code
if __name__ == '__main__':

    string = "geeksFORgeeks"

    # Remove nth index element
    i = 5

    # Print the new string
    print(remove(string, i))

Output:

geeksORgeeks