Python program to count number of vowels using sets in given string

Given a string, count the number of vowels present in given string using Sets. Prerequisite: Sets in Python Examples:

Input : GeeksforGeeks
Output : No. of vowels : 5

Input : Hello World
Output : No. of vowels :  3

Approach: 1. Create a set of vowels using set() and initialize a count variable to 0. 2. Traverse through the alphabets in the string and check if the letter in the string is present in set vowel. 3. If it is present, the vowel count is incremented. Below is the implementation of above approach: 

Python3

# Python3 code to count vowel in
# a string using set

# Function to count vowel
def vowel_count(str):

    # Initializing count variable to 0
    count = 0

    # Creating a set of vowels
    vowel = set("aeiouAEIOU")

    # Loop to traverse the alphabet
    # in the given string
    for alphabet in str:

        # If alphabet is present
        # in set vowel
        if alphabet in vowel:
            count = count + 1

    print("No. of vowels :", count)

# Driver code
str = "GeeksforGeeks"

# Function Call
vowel_count(str)

Output:

No. of vowels : 5

Time Complexity: O(n), where n is the length of the string. We traverse the string character by character and for each character, we do a constant time operation to check if it is a vowel or not.

Space Complexity: O(1). We only used constant extra space for setting up the set.

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