# Properties of Parallelograms

Parallelogram is a quadrilateral in which opposite sides are parallel and congruent and the opposite angles are equal. A parallelogram is formed by the intersection of two pairs of parallel lines.

## Important Properties of a Parallelogram

A parallelogram is a quadrilateral in which opposite sides are parallel and equal in length. Also, opposite angles are also equal. Few of the important properties of a parallelogram are:

- Opposite sides of a parallelogram are equal in length and are parallel to each other.
- Opposite angles in a parallelogram are equal.
- Sum of all interior angles of a parallelogram is 360Â°.
- Consecutive angles of a parallelogram are supplementary (180Â°).

## Properties of Parallelogram Diagonals

Various properties of the diagonal of a parallelogram are:

- Both diagonals of a parallelogram bisect each other.
- The parallelogram is bisected into two congruent triangles by each diagonal.
- By parallelogram law, Sum of squares of the diagonal of a parallelogram is equal to the sum of squares of all the sides of a parallelogram.

## Theorems on Properties of a Parallelogram

Few important theorems on properties of a Parallelogram are discussed below in this article:

### Theorem 1: Opposite sides of a parallelogram are equal.

**Given:** ABCD is a parallelogram

**To Prove:** AB = CD & DA = BC

**Proof:**

Given ABCD is a parallelogram. Therefore,

AB || DC & AD || BC

Now, AD || BC and AC is intersecting A and C respectively.

âˆ DAC = âˆ BCA…(i) [Alternate Interior Angles]

Now, AB || DC and AC is intersecting A and C respectively.

âˆ BAC = âˆ D …(ii) [Alternate Interior Angles]

Now, In Î”ADC & Î”CBA

âˆ DAC = âˆ BCA [ From (i) ]

AC = AC [ Common Side ]

âˆ DCA = âˆ BAC [ From (ii) ]So, by ASA(Angle-Side-Angle) criterion of congruence

Î”ADC â‰… Î”CBA

AB = CD & DA = BC [ Corresponding part of congruent triangles are equal ]

Hence Proved

**Converse of Theorem 1: If opposite sides are equal in a quadrilateral, then it is a parallelogram**

**Given:** Opposite sides in a quadrilateral ABCD are equal, AB = CD, and BC = AD.

**To Prove:** Quadrilateral ABCD is a parallelogram.

In quadrilateral ABCD, AB = CD and AD = BC. In triangles ABC, and CDA we have

AC = AC (Common sides)

AD = BC (given)

AB = CD (since alternate interior angles are equal)So by the SSS congruency criterion, triangles ABC, and CDA are congruent, thus by CPCT corresponding angles of triangles are equal. Thus, âˆ BAC = âˆ DCA, and âˆ BCA = âˆ DAC.

Now AB || CD, BC || AD and thus ABCD is a parallelogram.

### Theorem 2: Opposite angles of a parallelogram are equal.

**Given:** ABCD is a parallelogram

**To Prove: ** âˆ A = âˆ C and âˆ B = âˆ D

**Proof:**

Given ABCD is a parallelogram. Therefore,

AB || DC & AD || BC

Now, AB || DC and AD is Intersecting them at A and D respectively.

âˆ A + âˆ D = 180Âº …(i) [ Sum of consecutive interior angles is 180Âº]

Now, AD || BC and DC is Intersecting them at D and C respectively.

âˆ D + âˆ C = 180Âº …(ii) [ Sum of consecutive interior angles is 180Âº]

From (i) and (ii) , we get

âˆ A + âˆ D = âˆ D + âˆ C

So, âˆ A = âˆ C

Similarly, âˆ B = âˆ D

âˆ A = âˆ C and âˆ B = âˆ D

Hence Proved

### Converse of Theorem 2: If the opposite angles in a quadrilateral are equal, then it is a parallelogram

**Given:** In the quadrilateral ABCD âˆ A = âˆ C and âˆ B = âˆ D

**To Prove:** ABCD is a parallelogram.

**Proof:**

Given âˆ A = âˆ C and âˆ B = âˆ D in quadrilateral ABCD. We have to prove ABCD is a parallelogram

âˆ A + âˆ B + âˆ C + âˆ D = 360Âº (given âˆ A = âˆ C and âˆ B = âˆ D )

2(âˆ A + âˆ B) =360Âº

âˆ A + âˆ B = 180Âº.

Thus AD || BC. Similarly, we can show that AB || CD.

Hence, AD || BC, and AB || CD. Therefore ABCD is a parallelogram.

### Theorem 3: Diagonals of a parallelogram bisect each other.

**Given:** ABCD is a parallelogram

**To Prove:** OA = OC & OB = OD

**Proof:**

AB || DC & AD || BC

Now, AB || DC and AC is intersecting A and C respectively.

âˆ BAC = âˆ DCA [ Alternate Interior Angles are equal ]

So, âˆ BAO = âˆ DCO

Now, AB || DC and BD is intersecting B and D respectively.

âˆ ABD = âˆ CDB [ Alternate Interior Angles are equal ]

So, âˆ ABO = âˆ CDO

Now, in Î”AOB & Î”COD we have,

âˆ BAO = âˆ DCO [ Opposite sides of a parallelogram are equal ]

AB = CD

âˆ ABO = âˆ CDO

So, by ASA(Angle-Side-Angle) congruence criterion

Î”AOB â‰… Î”COD

OA = OC and OB = OD

Hence Proved

### Converse of Theorem 3: If the diagonals of a quadrilateral bisect each other, then it is a parallelogram.

**Given:** The diagonals AC and BD bisect each other.

**To Prove:** ABCD is a parallelogram.

**Proof:**

If the diagonals AB and CD bisect each other. Then in Î” AOB, and Î” COD

AO = CO (Diagonals bisect each other)

BO = DO (Diagonals bisect each other)

âˆ AOB =âˆ COD (vertically opposite angles)Thus, by SAS congruency criterion, triangles are congruent. So âˆ CAB = âˆ DCA, and âˆ DBA = âˆ CDB. Hence, AB || CD, and BC || AD. Thus ABCD is a parallelogram.

## Solved Example on Properties of Parallelogram

**Example 1: ABCD is a quadrilateral with AB = 10 cm. Diagonals of ABCD bisect each other at right angles. Then find the perimeter of ABCD.**

**Solution:**

We know that, if diagonals of a quadrilateral bisect each other at right angles then it is a rhombus.

Thus, ABCD is a rhombus and AB = BC = CD = DA.

Thus, the perimeter of ABCD = 4(AB) = 4(10) = 40 cm

**Example 2: Find area of a parallelogram where the base is 6 cm and the height is 12 cm.**

**Solution:**

Given, Base = 6 cm and Height = 12 cm.

We know,

Area = Base x Height

Area = 6 Ã— 12

Area = 72 cm

^{2}

## FAQs on Properties of a Parallelogram

**Question 1: What is a parallelogram?**

**Answer:**

A parallelogram is a quadrilateral that has in which opposite sides are parallel and equal. And opposite angles in a parallelogram equal. It is also considered as a cyclic quadrilateral.

**Question 2: Can a Rhombus be called a Parallelogram?**

**Answer:**

Opposite sides of a rhombus are equal and parallel, and its opposite angles are also equal. So it is considered a parallelogram.

**Question 3: What are the four important properties of a parallelogram?**

**Answer:**

The four important properties of the parallelogram are:

- Opposite sides of a parallelogram are parallel and congruent
- Consecutive angles of a parallelogram add up to 180 degrees
- Opposite angles of a parallelogram are equal
- Diagonals of a parallelogram bisect each other.

**Question 4: What is the order of rotational symmetry in a parallelogram?**

**Answer:**

Order of rotational symmetry is a parallelogram is 2.

**Question 5: Does a parallelogram have reflectional symmetry?**

**Answer:**

No, reflectional symmetry is not possible in a parallelogram.

**Question 6: Are the Diagonals of a Parallelogram Equal?**

**Answer:**

Diagonals of a parallelogram are generally NOT equal. In some special cases, parallelograms such as squares and rectangles have equal diagonals.

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