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Program to convert Java list of Strings to Seq in Scala

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  • Last Updated : 14 Jan, 2020
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A java list of Strings can be converted to sequence in Scala by utilizing toSeq method of Java in Scala. Here, we need to import Scala’s JavaConversions object in order to make this conversions work else an error will occur.
Now, lets see some examples and then discuss how it works in details.
Example:1#




// Scala program to convert Java list 
// to Sequence in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating list of Strings in Java
        val list = new java.util.ArrayList[String]()
          
        // Adding Strings to the list
        list.add("geeks")
        list.add("cs")
        list.add("portal")
          
        // Converting list to Sequence 
        val seq= list.toSeq
          
        // Displays seq
        println(seq)
      
    }
}


Output:

Buffer(geeks, cs, portal)

Example:2#




// Scala program to convert Java list 
// to Sequence in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating list of Strings in Java
        val list = new java.util.ArrayList[String]()
          
        // Adding Strings to the list
        list.add("i")
        list.add("am an")
        list.add("author")
          
        // Converting list to Sequence 
        val seq= list.toSeq
          
        // Displays seq
        println(seq)
          
    }
}


Output:

Buffer(i, am an, author)

My Personal Notes arrow_drop_up
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