Program to calculate area and perimeter of a rhombus whose diagonals are given
Given the length of diagonals of a rhombus, d1 and d2. The task is to find the perimeter and the area of that rhombus.
A rhombus is a polygon having 4 equal sides in which both the opposite sides are parallel, and opposite angles are equal.
Examples:
Input: d1 = 2 and d2 = 4 Output: The area of rhombus with diagonals 2 and 4 is 4. The perimeter of rhombus with diagonals 2 and 4 is 8. Input: d1 = 100 and d2 = 500 Output: The area of rhombus with diagonals 100 and 500 is 25000. The perimeter of rhombus with diagonals 100 and 500 is 1019.
Area of the rhombus =
Perimeterof the rhombus =
Below is the implementation of above approach:
C++
// C++ Program to calculate area and perimeter // of a rhombus using diagonals #include <iostream> #include <math.h> using namespace std; // calculate area and perimeter of a rhombus int rhombusAreaPeri( int d1, int d2) { long long int area, perimeter; area = (d1 * d2) / 2; perimeter = 2 * sqrt ( pow (d1, 2) + pow (d2, 2)); cout << "The area of rhombus with diagonals " << d1 << " and " << d2 << " is " << area << "." << endl; cout << "The perimeter of rhombus with diagonals " << d1 << " and " << d2 << " is " << perimeter << "." << endl; } // Driver code int main() { int d1 = 2, d2 = 4; rhombusAreaPeri(d1, d2); return 0; } |
Java
// Java program to calculate area and perimeter // of a rhombus using diagonals import java.io.*; class GFG { // calculate area and perimeter of a rhombus static int rhombusAreaPeri( int d1, int d2) { int area, perimeter; area = (d1 * d2) / 2 ; perimeter = ( int )( 2 * Math.sqrt(Math.pow(d1, 2 ) + Math.pow(d2, 2 ))); System.out.println( "The area of rhombus with diagonals " + d1 + " and " + d2 + " is " + area + "." ); System.out.println( "The perimeter of rhombus with diagonals " +d1 + " and " + d2 + " is " + perimeter + "." ); return 0 ; } // Driver code public static void main (String[] args) { int d1 = 2 , d2 = 4 ; rhombusAreaPeri(d1, d2); } } // This code is contributed by anuj_67.. |
Python3
# Python 3 Program to calculate # area and perimeter of a rhombus # using diagonals from math import sqrt, pow # calculate area and perimeter # of a rhombus def rhombusAreaPeri(d1, d2): area = (d1 * d2) / 2 perimeter = 2 * sqrt( pow (d1, 2 ) + pow (d2, 2 )) print ( "The area of rhombus with diagonals" , d1, "and" , d2, "is" , area, "." ) print ( "The perimeter of rhombus with diagonals" , d1, "and" , d2, "is" , perimeter, "." ) # Driver code if __name__ = = '__main__' : d1 = 2 d2 = 4 rhombusAreaPeri(d1, d2) # This code is contributed # by Surendra_Gangwar |
C#
// C# program to calculate area // and perimeter of a rhombus // using diagonals using System; class GFG { // calculate area and perimeter // of a rhombus static int rhombusAreaPeri( int d1, int d2) { int area, perimeter; area = (d1 * d2) / 2; perimeter = ( int )(2 * Math.Sqrt(Math.Pow(d1, 2) + Math.Pow(d2, 2))); Console.WriteLine( "The area of rhombus with " + "diagonals " + d1 + " and " + d2 + " is " + area + "." ); Console.WriteLine( "The perimeter of rhombus " + "with diagonals " + d1 + " and " + d2 + " is " + perimeter + "." ); return 0; } // Driver code public static void Main () { int d1 = 2, d2 = 4; rhombusAreaPeri(d1, d2); } } // This code is contributed by anuj_67.. |
PHP
<?php // PHP Program to calculate area // and perimeter of a rhombus // using diagonals // calculate area and perimeter // of a rhombus function rhombusAreaPeri( $d1 , $d2 ) { $area = ( $d1 * $d2 ) / 2; $perimeter = 2 * sqrt(pow( $d1 , 2) + pow( $d2 , 2)); echo "The area of rhombus with diagonals " . $d1 . " and " . $d2 . " is " . $area . "." . "\n" ; echo "The perimeter of rhombus with diagonals " . $d1 . " and " . $d2 . " is " . $perimeter . "." . "\n" ; } // Driver code $d1 = 2; $d2 = 4; rhombusAreaPeri( $d1 , $d2 ); // This code is contributed // by Akanksha Rai(Abby_akku) ?> |
Javascript
<script> // javascript Program to calculate area and perimeter // of a rhombus using diagonals // calculate area and perimeter of a rhombus function rhombusAreaPeri(d1, d2) { let area, perimeter; area = Math.floor((d1 * d2) / 2); perimeter = Math.floor(2 * Math.sqrt(Math.pow(d1, 2) + Math.pow(d2, 2))); document.write( "The area of rhombus with diagonals " + d1 + " and " + d2 + " is " + area + "." + "<br>" ); document.write( "The perimeter of rhombus with diagonals " + d1 + " and " + d2 + " is " + perimeter + "." + "<br>" ); } // Driver code let d1 = 2, d2 = 4; rhombusAreaPeri(d1, d2); // This code is contributed by Mayank Tyagi </script> |
Output:
The area of rhombus with diagonals 2 and 4 is 4. The perimeter of rhombus with diagonals 2 and 4 is 8.
Time Complexity: O(log(d12+d22))
Auxiliary Space: O(1), since no extra space has been taken.
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