Program for multiplication of array elements
We are given an array, and we have to calculate the product of an array using both iterative and recursive methods.
Examples:
Input : array[] = {1, 2, 3, 4, 5, 6}
Output : 720
Here, product of elements = 1*2*3*4*5*6 = 720Input : array[] = {1, 3, 5, 7, 9}
Output : 945
Iterative Method: We initialize result as 1. We traverse array from left to right and multiply elements with results.
Implementation:
C++
// Iterative C++ program to // multiply array elements #include<bits/stdc++.h> using namespace std; // Function to calculate the // product of the array int multiply( int array[], int n) { int pro = 1; for ( int i = 0; i < n; i++) pro = pro * array[i]; return pro; } // Driver Code int main() { int array[] = {1, 2, 3, 4, 5, 6}; int n = sizeof (array) / sizeof (array[0]); // Function call to calculate product cout << multiply(array, n); return 0; } |
Java
// Iterative Java program to // multiply array elements import java.io.*; public class GFG { static int arr[] = { 1 , 2 , 3 , 4 , 5 , 6 }; // Method to calculate the // product of the array static int multiply() { int pro = 1 ; for ( int i = 0 ; i < arr.length; i++) pro = pro * arr[i]; return pro; } // Driver Code public static void main(String[] args) { // Method call to calculate product System.out.println(multiply()); } } |
Python3
# Iterative Python3 code to # multiply list elements # Function to calculate # the product of the array def multiply( array , n ): pro = 1 for i in range (n): pro = pro * array[i] return pro # Driver code array = [ 1 , 2 , 3 , 4 , 5 , 6 ] n = len (array) # Function call to # calculate product print (multiply(array, n)) # This code is contributed # by "Sharad_Bhardwaj". |
C#
// Iterative C# program to // multiply array elements using System; class GFG { static int []arr = {1, 2, 3, 4, 5, 6}; // Method to calculate the // product of the array static int multiply() { int pro = 1; for ( int i = 0; i < arr.Length; i++) pro = pro * arr[i]; return pro; } // Driver Code public static void Main() { // Method call to calculate product Console.Write(multiply()); } } // This code is contributed by nitin mittal |
PHP
<?php // Iterative PHP program to // multiply array elements // Function to calculate the // product of the array function multiply( $arr , $n ) { $pro = 1; for ( $i = 0; $i < $n ; $i ++) $pro = $pro * $arr [ $i ]; return $pro ; } // Driver Code $arr = array (1, 2, 3, 4, 5, 6); $n = sizeof( $arr ) / sizeof( $arr [0]); // Function call to // calculate product echo multiply( $arr , $n ); return 0; // This code is contributed by nitin mittal. ?> |
Javascript
<script> // Iterative javascript program to // multiply array elements var arr = [ 1, 2, 3, 4, 5, 6 ]; // Method to calculate the // product of the array function multiply() { var pro = 1; for (i = 0; i < arr.length; i++) pro = pro * arr[i]; return pro; } // Driver Code // Method call to calculate product document.write(multiply()); // This code contributed by aashish1995 </script> |
720
Time Complexity: O(n)
Auxiliary Space: O(1)
Recursive Method:
C++
// Recursive C++ program to // multiply array elements #include<iostream> using namespace std; // Function to calculate the // product of array using recursion int multiply( int a[], int n) { // Termination condition if (n == 0) return (a[n]); else return (a[n] * multiply(a, n - 1)); } // Driver Code int main() { int array[] = {1, 2, 3, 4, 5, 6}; int n = sizeof (array) / sizeof (array[0]); // Function call to // calculate the product cout << multiply(array, n - 1) << endl; return 0; } |
Java
// Recursive Java program to // multiply array elements import java.io.*; public class GFG { static int arr[] = { 1 , 2 , 3 , 4 , 5 , 6 }; // Method to calculate the product // of the array using recursion static int multiply( int a[], int n) { // Termination condition if (n == 0 ) return (a[n]); else return (a[n] * multiply(a, n - 1 )); } // Driver Code public static void main(String[] args) { // Method call to // calculate product System.out.println(multiply(arr, arr.length - 1 )); } } |
Python3
# Recursive Python3 code # to multiply array elements # Function to calculate the product # of array using recursion def multiply( a , n ): # Termination condition if n = = 0 : return (a[n]) else : return (a[n] * multiply(a, n - 1 )) # Driver Code array = [ 1 , 2 , 3 , 4 , 5 , 6 ] n = len (array) # Function call to # calculate the product print (multiply(array, n - 1 )) # This code is contributed # by "Sharad_Bhardwaj". |
C#
// Recursive C# program to // multiply array elements using System; class GFG { static int []arr = {1, 2, 3, 4, 5, 6}; // Method to calculate the product // of the array using recursion static int multiply( int []a, int n) { // Termination condition if (n == 0) return (a[n]); else return (a[n] * multiply(a, n - 1)); } // Driver Code public static void Main() { // Method call to // calculate product Console.Write(multiply(arr, arr.Length - 1)); } } // This code is contributed by Nitin Mittal. |
PHP
<?php // Recursive PHP program to // multiply array elements // Function to calculate the // product of array using recursion function multiply( $a , $n ) { // Termination condition if ( $n == 0) return ( $a [ $n ]); else return ( $a [ $n ] * multiply( $a , $n - 1)); } // Driver Code $array = array (1, 2, 3, 4, 5, 6); $n = count ( $array ); // Function call to // calculate the product echo multiply( $array , $n - 1) // This code is contributed by anuj_67. ?> |
Javascript
<script> // Recursive javascript program to // multiply array elements var arr = [ 1, 2, 3, 4, 5, 6 ]; // Method to calculate the product // of the array using recursion function multiply(a , n) { // Termination condition if (n == 0) return (a[n]); else return (a[n] * multiply(a, n - 1)); } // Driver Code // Method call to // calculate product document.write(multiply(arr, arr.length - 1)); // This code is contributed by todaysgaurav </script> |
720
Time Complexity: O(n)
Auxiliary Space: O(n)
Using Library functions:
C++
// C++ program for multiplication of array elements #include <iostream> /*In C++, we can quickly find array product using accumulate() and multiplies<>() defined in numeric library*/ #include <numeric> using namespace std; // Function to calculate the // product of the array int multiply( int array[], int n) { // The pro specifies the initial value to be considered int pro = 1; /* Here accumulate() take 4 parameters: begening of array, end of array, the initial value and the binary operation function object that will be applied */ return accumulate(array, array + n, pro, multiplies< int >()); } int main() { int array[] = { 1, 2, 3, 4, 5, 6 }; // get length of array int n = sizeof (array) / sizeof (array[0]); cout << multiply(array, n); return 0; // This code is contributed by Shivesh Kumar Dwivedi } |
Java
// Java program for multiplication of array elements import java.util.Arrays; import java.util.function.IntBinaryOperator; public class GFG { // Function to calculate the product of the array public static int multiply( int [] array) { // The pro specifies the initial value to be // considered int pro = 1 ; /* Here Arrays.stream() method is used to get an IntStream of array, then reduce() method is used with the help of IntBinaryOperator interface and multiplies operation to perform the binary operation between the array elements and the initial value. */ return Arrays.stream(array).reduce( pro, new IntBinaryOperator() { @Override public int applyAsInt( int left, int right) { return left * right; } }); } public static void main(String[] args) { int [] array = { 1 , 2 , 3 , 4 , 5 , 6 }; // get length of array int n = array.length; System.out.println(multiply(array)); } } // this code is contributed by bhardwajji |
Python3
# python3 program for multiplication of array elements # In python3, we can quickly find array product using # reduce available in functools library from functools import reduce # Function to calculate the # product of the array def multiply(array, n): # The reduce() only takes the name of the array/list as a parameter return reduce (( lambda x, y: x * y), array) array = [ 1 , 2 , 3 , 4 , 5 , 6 ] # get length of array n = len (array) print (multiply(array, n)) # This code is contributed by Abhijeet Kumar(abhijeet19403) |
C#
// C# program for multiplication of array elements using System; // In C#, we can quickly find array // product using using the Aggregate // method from the System.Linq namespace using System.Linq; public class GFG { // Function to calculate the product of the array static int Multiply( int [] array, int n) { // The pro specifies the initial value to be // considered int pro = 1; // here Aggregate method takes two arguments // an initial value (in this case, pro) and a // delegate function that defines how to // aggregate the values in the array return array.Aggregate(pro, (current, t) = > current * t); } // Driver Code static public void Main( string [] args) { int [] array = { 1, 2, 3, 4, 5, 6 }; // get length of array int n = array.Length; Console.WriteLine(Multiply(array, n)); } } // This code is contributed by Prasad Kandekar(prasad264) |
Javascript
<script> // Function to calculate the product of the array function multiply(array) { // The pro specifies the initial value to be considered let pro = 1; /* Here the reduce() method is used with the help of an arrow function to perform the binary operation between the array elements and the initial value. */ return array.reduce((acc, cur) => acc * cur, pro); } let array = [1, 2, 3, 4, 5, 6]; // get length of array let n = array.length; console.log(multiply(array)); </script> |
720
Time Complexity: O(n)
Auxiliary Space: O(1)
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