# Program to find slope of a line

• Difficulty Level : Basic
• Last Updated : 08 Dec, 2022

Given two coordinates, find the slope of a straight line.

Examples:

```Input  : x1 = 4, y1 = 2,
x2 = 2, y2 = 5
Output : Slope is -1.5```

Approach: To calculate the slope of a line you need only two points from that line, (x1, y1) and (x2, y2). The equation used to calculate the slope from two points is:

Below is the implementation of the above approach:

## C++

 `// C++ program for slope of line` `#include ` `using` `namespace` `std;`   `// function to find the slope of a straight line` `float` `slope(``float` `x1, ``float` `y1, ``float` `x2, ``float` `y2)` `{` `    ``if` `(x2 - x1 != 0)` `        ``return` `(y2 - y1) / (x2 - x1);` `    ``return` `INT_MAX;` `}`   `// driver code to check the above function` `int` `main()` `{` `    ``float` `x1 = 4, y1 = 2;` `    ``float` `x2 = 2, y2 = 5;` `    ``cout << ``"Slope is: "` `<< slope(x1, y1, x2, y2);` `    ``return` `0;` `}`

## Java

 `// Java program for slope of line` `import` `java.io.*;`   `class` `GFG {` `    ``static` `float` `slope(``float` `x1, ``float` `y1, ``float` `x2,` `                       ``float` `y2)` `    ``{` `        ``if` `(x2 - x1 != ``0``)` `            ``return` `(y2 - y1) / (x2 - x1);` `        ``return` `Integer.MAX_VALUE;` `    ``}` `    ``public` `static` `void` `main(String[] args)` `    ``{` `        ``float` `x1 = ``4``, y1 = ``2``;` `        ``float` `x2 = ``2``, y2 = ``5``;` `        ``System.out.println(``"Slope is: "` `                           ``+ slope(x1, y1, x2, y2));` `    ``}` `}`

## Python

 `# Python program for slope of line` `def` `slope(x1, y1, x2, y2):` `    ``if``(x2 ``-` `x1 !``=` `0``):` `      ``return` `(``float``)(y2``-``y1)``/``(x2``-``x1)` `    ``return` `sys.maxint`     `# driver code` `x1 ``=` `4` `y1 ``=` `2` `x2 ``=` `2` `y2 ``=` `5` `print` `"Slope is:"``, slope(x1, y1, x2, y2)`

## C#

 `using` `System;`   `public` `static` `class` `GFG {` `    ``// C# program for slope of line`   `    ``// function to find the slope of a straight line` `    ``public` `static` `float` `slope(``float` `x1, ``float` `y1, ``float` `x2,` `                              ``float` `y2)` `    ``{` `        ``if` `(x2 - x1 != 0F) {` `            ``return` `(y2 - y1) / (x2 - x1);` `        ``}` `        ``return` `int``.MaxValue;` `    ``}`   `    ``// driver code to check the above function` `    ``internal` `static` `void` `Main()` `    ``{` `        ``float` `x1 = 4F;` `        ``float` `y1 = 2F;` `        ``float` `x2 = 2F;` `        ``float` `y2 = 5F;` `        ``Console.Write(``"Slope is: "``);` `        ``Console.Write(slope(x1, y1, x2, y2));` `    ``}` `}`   `// The code is contributed by Aarti_Rathi`

## PHP

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## Javascript

 `// C Javascript program for slope of line`   `// function to find the slope of a straight line` `function` `slope(x1, y1, x2, y2)` `{` `    ``if` `(x2 - x1 != 0)` `    ``{` `        ``return` `(y2 - y1) / (x2 - x1);` `    ``}` `    ``return` `Number.MAX_VALUE;` `}`   `// driver code to check the above function` `var` `x1 = 4;` `var` `y1 = 2;` `var` `x2 = 2;` `var` `y2 = 5;` `console.log(``"Slope is: "` `+ slope(x1, y1, x2, y2));`   `// The code is contributed by Aarti_Rathi`

Output

`Slope is: -1.5`

Time Complexity: O(1)
Auxiliary Space: O(1)

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