Print uncommon elements from two sorted arrays
Given two sorted arrays of distinct elements, we need to print those elements from both arrays that are not common. The output should be printed in sorted order.
Examples :
Input : arr1[] = {10, 20, 30} arr2[] = {20, 25, 30, 40, 50} Output : 10 25 40 50 We do not print 20 and 30 as these elements are present in both arrays. Input : arr1[] = {10, 20, 30} arr2[] = {40, 50} Output : 10 20 30 40 50
The idea is based on merge process of merge sort. We traverse both arrays and skip common elements.
Implementation:
C++
// C++ program to find uncommon elements of // two sorted arrays #include <bits/stdc++.h> using namespace std; void printUncommon( int arr1[], int arr2[], int n1, int n2) { int i = 0, j = 0, k = 0; while (i < n1 && j < n2) { // If not common, print smaller if (arr1[i] < arr2[j]) { cout << arr1[i] << " " ; i++; k++; } else if (arr2[j] < arr1[i]) { cout << arr2[j] << " " ; k++; j++; } // Skip common element else { i++; j++; } } // printing remaining elements while (i < n1) { cout << arr1[i] << " " ; i++; k++; } while (j < n2) { cout << arr2[j] << " " ; j++; k++; } } // Driver code int main() { int arr1[] = {10, 20, 30}; int arr2[] = {20, 25, 30, 40, 50}; int n1 = sizeof (arr1) / sizeof (arr1[0]); int n2 = sizeof (arr2) / sizeof (arr2[0]); printUncommon(arr1, arr2, n1, n2); return 0; } |
Java
// Java program to find uncommon elements // of two sorted arrays import java.io.*; class GFG { static void printUncommon( int arr1[], int arr2[], int n1, int n2) { int i = 0 , j = 0 , k = 0 ; while (i < n1 && j < n2) { // If not common, print smaller if (arr1[i] < arr2[j]) { System.out.print(arr1[i] + " " ); i++; k++; } else if (arr2[j] < arr1[i]) { System.out.print(arr2[j] + " " ); k++; j++; } // Skip common element else { i++; j++; } } // printing remaining elements while (i < n1) { System.out.print(arr1[i] + " " ); i++; k++; } while (j < n2) { System.out.print(arr2[j] + " " ); j++; k++; } } // Driver code public static void main(String[] args) { int arr1[] = { 10 , 20 , 30 }; int arr2[] = { 20 , 25 , 30 , 40 , 50 }; int n1 = arr1.length; int n2 = arr2.length; printUncommon(arr1, arr2, n1, n2); } } // This code is contributed by vt_m |
Python3
# Python 3 program to find uncommon # elements of two sorted arrays def printUncommon(arr1, arr2, n1, n2) : i = 0 j = 0 k = 0 while (i < n1 and j < n2) : # If not common, print smaller if (arr1[i] < arr2[j]) : print ( arr1[i] , end = " " ) i = i + 1 k = k + 1 elif (arr2[j] < arr1[i]) : print ( arr2[j] , end = " " ) k = k + 1 j = j + 1 # Skip common element else : i = i + 1 j = j + 1 # printing remaining elements while (i < n1) : print ( arr1[i] , end = " " ) i = i + 1 k = k + 1 while (j < n2) : print ( arr2[j] , end = " " ) j = j + 1 k = k + 1 # Driver code arr1 = [ 10 , 20 , 30 ] arr2 = [ 20 , 25 , 30 , 40 , 50 ] n1 = len (arr1) n2 = len (arr2) printUncommon(arr1, arr2, n1, n2) # This code is contributed # by Nikita Tiwari. |
C#
// C# program to find uncommon elements // of two sorted arrays using System; class GFG { static void printUncommon( int []arr1, int []arr2, int n1, int n2) { int i = 0, j = 0, k = 0; while (i < n1 && j < n2) { // If not common, print smaller if (arr1[i] < arr2[j]) { Console.Write(arr1[i] + " " ); i++; k++; } else if (arr2[j] < arr1[i]) { Console.Write(arr2[j] + " " ); k++; j++; } // Skip common element else { i++; j++; } } // printing remaining elements while (i < n1) { Console.Write(arr1[i] + " " ); i++; k++; } while (j < n2) { Console.Write(arr2[j] + " " ); j++; k++; } } // Driver Code public static void Main() { int []arr1 = {10, 20, 30}; int []arr2 = {20, 25, 30, 40, 50}; int n1 = arr1.Length; int n2 = arr2.Length; printUncommon(arr1, arr2, n1, n2); } } // This code is contributed by Sam007 |
PHP
<?php // PHP program to find uncommon // elements of two sorted arrays function printUncommon( $arr1 , $arr2 , $n1 , $n2 ) { $i = 0; $j = 0; $k = 0; while ( $i < $n1 && $j < $n2 ) { // If not common, print smaller if ( $arr1 [ $i ] < $arr2 [ $j ]) { echo $arr1 [ $i ] . " " ; $i ++; $k ++; } else if ( $arr2 [ $j ] < $arr1 [ $i ]) { echo $arr2 [ $j ] . " " ; $k ++; $j ++; } // Skip common element else { $i ++; $j ++; } } // printing remaining elements while ( $i < $n1 ) { echo $arr1 [ $i ] . " " ; $i ++; $k ++; } while ( $j < $n2 ) { echo $arr2 [ $j ] . " " ; $j ++; $k ++; } } // Driver code $arr1 = array (10, 20, 30); $arr2 = array (20, 25, 30, 40, 50); $n1 = sizeof( $arr1 ) ; $n2 = sizeof( $arr2 ) ; printUncommon( $arr1 , $arr2 , $n1 , $n2 ); // This code is contributed by Anuj_67 ?> |
Javascript
<script> // JavaScript program to find uncommon elements // of two sorted arrays function printUncommon(arr1, arr2, n1, n2) { let i = 0, j = 0, k = 0; while (i < n1 && j < n2) { // If not common, print smaller if (arr1[i] < arr2[j]) { document.write(arr1[i] + " " ); i++; k++; } else if (arr2[j] < arr1[i]) { document.write(arr2[j] + " " ); k++; j++; } // Skip common element else { i++; j++; } } // printing remaining elements while (i < n1) { document.write(arr1[i] + " " ); i++; k++; } while (j < n2) { document.write(arr2[j] + " " ); j++; k++; } } // Driver Code let arr1 = [ 10, 20, 30 ]; let arr2 = [ 20, 25, 30, 40, 50 ]; let n1 = arr1.length; let n2 = arr2.length; printUncommon(arr1, arr2, n1, n2); // This code is contributed by susmitakundugoaldanga. </script> |
Output :
10 25 40 50
Time Complexity : O(n1 + n2)
Auxiliary Space : O(1)
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