Print powers using Anonymous Function in Python

Prerequisite : Anonymous function In the program below, we have used anonymous (lambda) function inside the map() built-in function to find the powers of 2. In Python, anonymous function is defined without a name. While normal functions are defined using the def keyword, in Python anonymous functions are defined using the lambda keyword. Hence, anonymous functions are also called lambda functions. Syntax: 

lambda arguments: expression

Lambda functions can have any number of arguments but only one expression. The expression is evaluated and returned Example:

Input : ('The total terms is:', 10)

Output :
('2 raised to power', 0, 'is', 1)
('2 raised to power', 1, 'is', 2)
('2 raised to power', 2, 'is', 4)
('2 raised to power', 3, 'is', 8)
('2 raised to power', 4, 'is', 16)
('2 raised to power', 5, 'is', 32)
('2 raised to power', 6, 'is', 64)
('2 raised to power', 7, 'is', 128)
('2 raised to power', 8, 'is', 256)
('2 raised to power', 9, 'is', 512)

Python

# Python Program to display the powers
# of 2 using anonymous function

# Change this value for a different result
terms = 10

# Uncomment to take number of terms from user
# terms = int(input("How many terms? "))

# use anonymous function
result = list(map(lambda x: 2 ** x, range(terms)))

# display the result
print("The total terms is:", terms)
for i in range(terms):
print("2 raised to power", i, "is", result[i])

Output:

('The total terms is:', 10)
('2 raised to power', 0, 'is', 1)
('2 raised to power', 1, 'is', 2)
('2 raised to power', 2, 'is', 4)
('2 raised to power', 3, 'is', 8)
('2 raised to power', 4, 'is', 16)
('2 raised to power', 5, 'is', 32)
('2 raised to power', 6, 'is', 64)
('2 raised to power', 7, 'is', 128)
('2 raised to power', 8, 'is', 256)
('2 raised to power', 9, 'is', 512)

Time Complexity: O(n)

Auxiliary Space: O(1)

My Personal Notes arrow_drop_up

Save