Numerical Methods and Calculus
Question 1 |
Which one of the following functions is continuous at x = 3?

C | |
D | |
B | |
A |
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A function is continuous at some point c,
Value of f(x) defined for x > c = Value of f(x) defined for x < c = Value of f(x) defined for x = c
All values are 2 in option A
Question 2 |
Function f is known at the following points:

9.003 | |
9.017 | |
8.983 | |
9.045 |
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Question 3 |
Consider the function f(x) = sin(x) in the interval [π/4, 7π/4]. The number and location(s) of the local minima of this function are
One, at π/2 | |
One, at 3π/2 | |
Two, at π/2 and 3π/2 | |
Two, at π/4 and 3π/2 |
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Question 4 |
The bisection method is applied to compute a zero of the function f(x) = x4 – x3 – x2 – 4 in the
interval [1,9]. The method converges to a solution after ––––– iterations
5 | |
7 | |
3 | |
1 |
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In bisection method, we calculate the values at extreme points of given interval, if signs of values are opposite, then we find the middle point. Whatever sign we get at middle point, we take the corner point of opposite sign and repeat the process till we get 0.
f(1) < 0 and f(9) > 0
mid = (1 + 9)/2 = 5
f(5) > 0, so zero value lies in [1, 5]
mid = (1+5)/2 = 3
f(3) > 0, so zero value lies in [1, 3]
mid = (1+3)/2 = 2
f(2) = 0
Question 5 |
Given i=√-1, what will be the evaluation of the integral ?
2 | |
-i | |
0 | |
i |
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Question 6 |
Newton-Raphson method is used to compute a root of the equation x2-13=0 with 3.5 as the initial value. The approximation after one iteration is
3.667 | |
3.607 | |
3.676 | |
3.575 |
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In Newton-Raphson's method, We use the following formula to get the next value of f(x). f'(x) is derivative of f(x).
f(x) = x2-13 f'(x) = 2x Applying the above formula, we get Next x = 3.5 - (3.5*3.5 - 13)/2*3.5 Next x = 3.607
Question 7 |
What is the value of Limn->∞(1-1/n)2n ?
1 | |
e-2 | |
e-1/2 | |
0 |
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Question 8 |
Two alternative packages A and B are available for processing a database having 10k records. Package A requires 0.0001n2 time units and package B requires 10nlog10n time units to process n records. What is the smallest value of k for which package B will be preferred over A?
12 | |
10 | |
6 | |
5 |
Discuss it
Since, 10nlog10n ≤ 0.0001n2
Given n = 10k records.
Therefore,
⟹10×(10k)log1010k ≤ 0.0001(10k)2
⟹10k+1k ≤ 0.0001 × 102k
⟹k ≤ 102k−k−1−4
⟹k ≤ 10k−5
Hence, value 5 does not satisfy but value 6 satisfies. 6 is the smallest value of k for which package B will be preferred over A. Option (C) is correct.
Question 9 |
0 | |
1 | |
ln 2 | |
1/2 ln 2 |
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