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Node.js URLSearchParams.getAll()

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  • Last Updated : 14 Oct, 2021
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In URLSearchParams interface, the getAll() method returns all the values of the input search parameter in the form of an array.

Syntax:

URLSearchParams.getAll(name)

Returns: An array of string according to the name-value pairs, else an empty array will be returned.

Parameters:
name – Input the name of the parameter.

Example1:




let url = new URL('https://example.com?par=5&bar=2'); 
let params = new URLSearchParams(url.search.slice(1)); 
  
//Add a second par parameter. 
params.append('par', 4);
  
console.log(params.getAll('par'))'


Output:

['5', '4']

Example2: When input parameter is not present




let params = new URLSearchParams(url.search.slice(1)); 
  
console.log(params.getAll('bar'))'


Output:

['2','7','9']

Supported Browsers:

  • Google Chrome
  • IE
  • Edge
  • Opera
  • Apple Safari
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