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# Modulo Operator (%) in C/C++ with Examples

The modulo operator, denoted by %, is an arithmetic operator. The modulo division operator produces the remainder of an integer division which is also called the modulus of the operation.

## Syntax of Modulus Operator

If x and y are integers, then the expression:

`x % y;`

### Return Value of Modulus Operator

• If y completely divides x, the result of the expression is 0.
• If x is not completely divisible by y, then the result will be the remainder in the range [0, y-1]
• (x % y) < (x / 2) ………if (x >= y)
• (x % y) = x ……… if (x < y)
• If y is 0, then division by zero is a compile-time error.

## Example of Modulus Operator

Below is the C/C++ program to demonstrate the working of the modulo operator:

## C

 `// C Program to illustrate the working of modulo operator` `#include `   `int` `main(``void``)` `{` `    ``int` `x, y;`   `    ``int` `result;`   `    ``x = 3;` `    ``y = 4;` `    ``// using modulo operator` `    ``result = x % y;` `    ``printf``(``"%d"``, result);`   `    ``result = y % x;` `    ``printf``(``"\n%d"``, result);`   `    ``// for different values` `    ``x = 4;` `    ``y = 2;` `    ``result = x % y;` `    ``printf``(``"\n%d"``, result);`   `    ``return` `0;` `}`

## C++

 `// C++ Program to demonstrate the working of modulo operator` `#include `   `using` `namespace` `std;`   `// Driver code` `int` `main(``void``)` `{` `    ``int` `x, y;`   `    ``int` `result;`   `    ``x = 3;` `    ``y = 4;`   `    ``// using modulo operator` `    ``result = x % y;` `    ``cout << result << endl;`   `    ``result = y % x;` `    ``cout << result << endl;`   `    ``// for different values` `    ``x = 4;` `    ``y = 2;`   `    ``result = x % y;` `    ``cout << result;`   `    ``return` `0;` `}`   `//    This code is contributed by Mayank Tyagi`

## Restrictions on the Modulo Operator

The modulo operator has quite some restrictions or limitations.

The % operator cannot be applied to floating-point numbers i.e float or double. If you try to use the modulo operator with floating-point constants or variables, the compiler will produce an error.

## C

 `// C Program to illustrate the working of modulo operator` `#include `   `int` `main(``void``)` `{` `    ``float` `x, y;`   `    ``float` `result;`   `    ``x = 2.3;` `    ``y = 1.5;`   `    ``// modulo for floating point values` `    ``result = x % y;` `    ``printf``(``"%f"``, result);`   `    ``return` `0;` `}`

## C++

 `// C++ Program to demonstrate the restrictions of modulo` `// operator` `#include ` `using` `namespace` `std;`   `// Driver code` `int` `main()` `{` `    ``float` `x, y;`   `    ``x = 2.3;` `    ``y = 1.5;`   `    ``// modulo for floating point values` `    ``result = x % y;` `    ``cout << result;`   `    ``return` `0;` `}`   `// This code is contributed by Harshit Srivastava`

Output

```Compilation Error in C code :- prog.c: In function 'main':
prog.c:19:16: error:
invalid operands to binary % (have 'float' and 'float')
result = x % y;
^           ```

## Modulo Operator for Negative Operands

The sign of the result for the modulo operator is machine-dependent for negative operands, as the action takes as a result of underflow or overflow.

## C

 `// C Program to illustrate the working of the modulo` `// operator with negative operands` `#include `   `int` `main(``void``)` `{` `    ``int` `x, y;`   `    ``int` `result;`   `    ``x = -3;` `    ``y = 4;`   `    ``// modulo for negative operands` `    ``result = x % y;` `    ``printf``(``"%d"``, result);`   `    ``x = 4;` `    ``y = -2;` `    ``result = x % y;` `    ``printf``(``"\n%d"``, result);`   `    ``x = -3;` `    ``y = -4;` `    ``result = x % y;` `    ``printf``(``"\n%d"``, result);`   `    ``return` `0;` `}`

## C++

 `// C++ Program to demonstrate the working of the modulo` `// operator for negative operands` `#include ` `using` `namespace` `std;`   `// Driver code` `int` `main(``void``)` `{` `    ``int` `x, y;`   `    ``int` `result;`   `    ``x = -3;` `    ``y = 4;`   `    ``// modulo for negative operands` `    ``result = x % y;` `    ``cout << result << endl;`   `    ``x = 4;` `    ``y = -2;` `    ``result = x % y;` `    ``cout << result << endl;`   `    ``x = -3;` `    ``y = -4;` `    ``result = x % y;` `    ``cout << result;`   `    ``return` `0;` `}`   `// This code is contributed by Harshit Srivastava`

Output

```-3
0
-3```

Note: The return value in this case is compiler dependent.

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