# Mean of minimum of all possible K-size subsets from first N natural numbers

Given two positive integers **N** and **K**, the task is to find the mean of the minimum of all possible subsets of **size K** from the first **N** natural numbers.

**Examples:**

Input:N = 3, K = 2Output:1.33333Explanation:

All possible subsets of size K are {1, 2}, {1, 3}, {2, 3}. The minimum values in all the subsets are 1, 1, and 2 respectively. The mean of all the minimum values is (1 + 1 + 2)/3 = 1.3333.

Input:N = 3, K = 1Output:2.00000

**Naive Approach:** The simplest approach to solve the given problem is to find all the subsets formed from elements **[1, N]** and find the mean of all the minimum elements of the subsets of size **K**.

**Time Complexity:** O(N*2^{N})**Auxiliary Space:** O(1)

**Efficient Approach:** The above approach can also be optimized by observing the fact that the total number of subsets formed of **size K** is given by ** ^{N}C_{K}** and each element say

**i**occurs

**number of times as the minimum element.**

^{(N – i)}C_{(K – 1)}Therefore, the idea is to find the sum of **( ^{N – i}C_{K – 1)})*i** over all possible values of

**i**and divide it by the total number of subsets formed i.e.,

**.**

^{N}C_{K}Below is the implementation of the above approach:

## C++

`// C++ program for the above approach` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Function to find the value of nCr` `int` `nCr(` `int` `n, ` `int` `r, ` `int` `f[])` `{` ` ` `// Base Case` ` ` `if` `(n < r) {` ` ` `return` `0;` ` ` `}` ` ` `// Find nCr recursively` ` ` `return` `f[n] / (f[r] * f[n - r]);` `}` `// Function to find the expected minimum` `// values of all the subsets of size K` `int` `findMean(` `int` `N, ` `int` `X)` `{` ` ` `// Find the factorials that will` ` ` `// be used later` ` ` `int` `f[N + 1];` ` ` `f[0] = 1;` ` ` `// Find the factorials` ` ` `for` `(` `int` `i = 1; i <= N; i++) {` ` ` `f[i] = f[i - 1] * i;` ` ` `}` ` ` `// Total number of subsets` ` ` `int` `total = nCr(N, X, f);` ` ` `// Stores the sum of minimum over` ` ` `// all possible subsets` ` ` `int` `count = 0;` ` ` `// Iterate over all possible minimum` ` ` `for` `(` `int` `i = 1; i <= N; i++) {` ` ` `count += nCr(N - i, X - 1, f) * i;` ` ` `}` ` ` `// Find the mean over all subsets` ` ` `double` `E_X = ` `double` `(count) / ` `double` `(total);` ` ` `cout << setprecision(10) << E_X;` ` ` `return` `0;` `}` `// Driver Code` `int` `main()` `{` ` ` `int` `N = 3, X = 2;` ` ` `findMean(N, X);` ` ` `return` `0;` `}` |

## Java

`// Java program for the above approach` `import` `java.util.*;` `class` `GFG {` ` ` `// Function to find the value of nCr` ` ` `static` `int` `nCr(` `int` `n, ` `int` `r, ` `int` `f[]) {` ` ` `// Base Case` ` ` `if` `(n < r) {` ` ` `return` `0` `;` ` ` `}` ` ` `// Find nCr recursively` ` ` `return` `f[n] / (f[r] * f[n - r]);` ` ` `}` ` ` `// Function to find the expected minimum` ` ` `// values of all the subsets of size K` ` ` `static` `int` `findMean(` `int` `N, ` `int` `X) {` ` ` `// Find the factorials that will` ` ` `// be used later` ` ` `int` `[] f = ` `new` `int` `[N + ` `1` `];` ` ` `f[` `0` `] = ` `1` `;` ` ` `// Find the factorials` ` ` `for` `(` `int` `i = ` `1` `; i <= N; i++) {` ` ` `f[i] = f[i - ` `1` `] * i;` ` ` `}` ` ` `// Total number of subsets` ` ` `int` `total = nCr(N, X, f);` ` ` `// Stores the sum of minimum over` ` ` `// all possible subsets` ` ` `int` `count = ` `0` `;` ` ` `// Iterate over all possible minimum` ` ` `for` `(` `int` `i = ` `1` `; i <= N; i++) {` ` ` `count += nCr(N - i, X - ` `1` `, f) * i;` ` ` `}` ` ` `// Find the mean over all subsets` ` ` `double` `E_X = (` `double` `) (count) / (` `double` `) (total);` ` ` `System.out.print(String.format(` `"%.6f"` `, E_X));` ` ` `return` `0` `;` ` ` `}` ` ` `// Driver Code` ` ` `public` `static` `void` `main(String[] args) {` ` ` `int` `N = ` `3` `, X = ` `2` `;` ` ` `findMean(N, X);` ` ` `}` `}` `// This code contributed by Princi Singh` |

## Python3

`# Python 3 program for the above approach` `# Function to find the value of nCr` `def` `nCr(n, r, f):` ` ` ` ` `# Base Case` ` ` `if` `(n < r):` ` ` `return` `0` ` ` `# Find nCr recursively` ` ` `return` `f[n] ` `/` `(f[r] ` `*` `f[n ` `-` `r])` `# Function to find the expected minimum` `# values of all the subsets of size K` `def` `findMean(N, X):` ` ` ` ` `# Find the factorials that will` ` ` `# be used later` ` ` `f ` `=` `[` `0` `for` `i ` `in` `range` `(N ` `+` `1` `)]` ` ` `f[` `0` `] ` `=` `1` ` ` `# Find the factorials` ` ` `for` `i ` `in` `range` `(` `1` `,N` `+` `1` `,` `1` `):` ` ` `f[i] ` `=` `f[i ` `-` `1` `] ` `*` `i` ` ` `# Total number of subsets` ` ` `total ` `=` `nCr(N, X, f)` ` ` `# Stores the sum of minimum over` ` ` `# all possible subsets` ` ` `count ` `=` `0` ` ` `# Iterate over all possible minimum` ` ` `for` `i ` `in` `range` `(` `1` `,N` `+` `1` `,` `1` `):` ` ` `count ` `+` `=` `nCr(N ` `-` `i, X ` `-` `1` `, f) ` `*` `i` ` ` `# Find the mean over all subsets` ` ` `E_X ` `=` `(count) ` `/` `(total)` ` ` `print` `(` `"{0:.9f}"` `.` `format` `(E_X))` ` ` `return` `0` `# Driver Code` `if` `__name__ ` `=` `=` `'__main__'` `:` ` ` `N ` `=` `3` ` ` `X ` `=` `2` ` ` `findMean(N, X)` ` ` `# This code is contributed by ipg201607.` |

## C#

`// C# code for the above approach ` `using` `System;` `public` `class` `GFG` `{` ` ` `// Function to find the value of nCr` ` ` `static` `int` `nCr(` `int` `n, ` `int` `r, ` `int` `[] f)` ` ` `{` ` ` ` ` `// Base Case` ` ` `if` `(n < r) {` ` ` `return` `0;` ` ` `}` ` ` `// Find nCr recursively` ` ` `return` `f[n] / (f[r] * f[n - r]);` ` ` `}` ` ` `// Function to find the expected minimum` ` ` `// values of all the subsets of size K` ` ` `static` `int` `findMean(` `int` `N, ` `int` `X)` ` ` `{` ` ` ` ` `// Find the factorials that will` ` ` `// be used later` ` ` `int` `[] f = ` `new` `int` `[N + 1];` ` ` `f[0] = 1;` ` ` `// Find the factorials` ` ` `for` `(` `int` `i = 1; i <= N; i++) {` ` ` `f[i] = f[i - 1] * i;` ` ` `}` ` ` `// Total number of subsets` ` ` `int` `total = nCr(N, X, f);` ` ` `// Stores the sum of minimum over` ` ` `// all possible subsets` ` ` `int` `count = 0;` ` ` `// Iterate over all possible minimum` ` ` `for` `(` `int` `i = 1; i <= N; i++) {` ` ` `count += nCr(N - i, X - 1, f) * i;` ` ` `}` ` ` `// Find the mean over all subsets` ` ` `double` `E_X = (` `double` `) (count) / (` `double` `) (total);` ` ` `Console.Write(` `"{0:F9}"` `, E_X);` ` ` `return` `0;` ` ` `}` ` ` `// Driver Code` ` ` `static` `public` `void` `Main (){` ` ` `// Code` ` ` `int` `N = 3, X = 2;` ` ` `findMean(N, X);` ` ` `}` `}` `// This code is contributed by Potta Lokesh` |

## Javascript

`<script>` `// Javascript program for the above approach` `// Function to find the value of nCr` `function` `nCr(n, r, f) {` ` ` `// Base Case` ` ` `if` `(n < r) {` ` ` `return` `0;` ` ` `}` ` ` `// Find nCr recursively` ` ` `return` `f[n] / (f[r] * f[n - r]);` `}` `// Function to find the expected minimum` `// values of all the subsets of size K` `function` `findMean(N, X) {` ` ` `// Find the factorials that will` ` ` `// be used later` ` ` `let f = ` `new` `Array(N + 1).fill(0);` ` ` `f[0] = 1;` ` ` `// Find the factorials` ` ` `for` `(let i = 1; i <= N; i++) {` ` ` `f[i] = f[i - 1] * i;` ` ` `}` ` ` `// Total number of subsets` ` ` `let total = nCr(N, X, f);` ` ` `// Stores the sum of minimum over` ` ` `// all possible subsets` ` ` `let count = 0;` ` ` `// Iterate over all possible minimum` ` ` `for` `(let i = 1; i <= N; i++) {` ` ` `count += nCr(N - i, X - 1, f) * i;` ` ` `}` ` ` `// Find the mean over all subsets` ` ` `let E_X = count / total;` ` ` `document.write(parseFloat(E_X).toFixed(9));` ` ` `return` `0;` `}` `// Driver Code` `let N = 3,` ` ` `X = 2;` `findMean(N, X);` `// This code is contributed by gfgking.` `</script>` |

**Output:**

1.333333333

**Time Complexity:** O(N)**Auxiliary Space:** O(N)

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