# Maximum occurring character in an input string | Set-2

• Difficulty Level : Easy
• Last Updated : 11 Mar, 2022

Given a string containing lowercase characters. The task is to print the maximum occurring character in the input string. If 2 or more characters appear the same number of times, print the lexicographically (alphabetically) lowest (first) character.
Examples:

Input: test sample
Output:
‘t’, ‘e’ and ‘s’ appears 2 times, but ‘e’ is the lexicographically smallest character.
Input: sample program
Output: a

In the previous article, if there are more than one characters occurring the maximum number of time, then any of the characters is returned. In this post, the lexicographically smallest character of all the characters is returned.
Approach: Declare a freq array which is used as a hash table to store the frequencies of each character in the input string. Iterate in the string and increase the count of freq[s[i]] for every character. Traverse the freq[] array from left to right and keep track of the character having the maximum frequency so far. The value at freq[i] represents the frequency of character (i + ‘a’).
Below is the implementation of the above approach:

## C++

 `// C++ implementation to find` `// the maximum occurring character in` `// an input string which is lexicographically first` `#include ` `using` `namespace` `std;`   `// function to find the maximum occurring character in` `// an input string which is lexicographically first` `char` `getMaxOccurringChar(``char` `str[])` `{` `    ``// freq[] used as hash table` `    ``int` `freq = { 0 };`   `    ``// to store maximum frequency` `    ``int` `max = -1;`   `    ``// to store the maximum occurring character` `    ``char` `result;`   `    ``// length of 'str'` `    ``int` `len = ``strlen``(str);`   `    ``// get frequency of each character of 'str'` `    ``for` `(``int` `i = 0; i < len; i++)` `        ``freq[str[i]]++;`   `    ``// for each character, where character is obtained by` `    ``// (i + 'a') check whether it is the maximum character` `    ``// so far and accodingly update 'result'` `    ``for` `(``int` `i = 0; i < 26; i++)` `        ``if` `(max < freq[i]) {` `            ``max = freq[i];` `            ``result = (``char``)(i + ``'a'``);` `        ``}`   `    ``// maximum occurring character` `    ``return` `result;` `}`   `// Driver Code` `int` `main()` `{` `    ``char` `str[] = ``"sample program"``;` `    ``cout << ``"Maximum occurring character = "` `         ``<< getMaxOccurringChar(str);` `    ``return` `0;` `}`

## Java

 `// Java implementation to find` `// the maximum occurring character in` `// an input string which is lexicographically first`   `class` `GFG {`   `// function to find the maximum occurring character in` `// an input string which is lexicographically first` `    ``static` `char` `getMaxOccurringChar(``char` `str[]) {` `        ``// freq[] used as hash table` `        ``int` `freq[] = ``new` `int``[``26``];`   `        ``// to store maximum frequency` `        ``int` `max = -``1``;`   `        ``// to store the maximum occurring character` `        ``char` `result = ``0``;`   `        ``// length of 'str'` `        ``int` `len = str.length;`   `        ``// get frequency of each character of 'str'` `        ``for` `(``int` `i = ``0``; i < len; i++) {` `            ``if` `(str[i] != ``' '``) {` `                ``freq[str[i] - ``'a'``]++;` `            ``}` `        ``}`   `        ``// for each character, where character is obtained by` `        ``// (i + 'a') check whether it is the maximum character` `        ``// so far and accodingly update 'result'` `        ``for` `(``int` `i = ``0``; i < ``26``; i++) {` `            ``if` `(max < freq[i]) {` `                ``max = freq[i];` `                ``result = (``char``) (i + ``'a'``);` `            ``}` `        ``}`   `        ``// maximum occurring character` `        ``return` `result;` `    ``}`   `// Driver Code` `    ``public` `static` `void` `main(String[] args) {` `        ``char` `str[] = ``"sample program"``.toCharArray();` `        ``System.out.println(``"Maximum occurring character = "` `                ``+ getMaxOccurringChar(str));` `    ``}` `} `   `// This code is contributed by 29AjayKumar `

## Python3

 `# Python 3 implementation to find the ` `# maximum occurring character in an input ` `# string which is lexicographically first`   `# function to find the maximum occurring ` `# character in an input string which is ` `# lexicographically first` `def` `getMaxOccurringChar(``str``):` `    `  `    ``# freq[] used as hash table` `    ``freq ``=` `[``0` `for` `i ``in` `range``(``100``)] `   `    ``# to store maximum frequency` `    ``max` `=` `-``1`   `    ``# to store the maximum occurring` `    ``# character length of 'str'` `    ``len__ ``=` `len``(``str``)`   `    ``# get frequency of each character of 'str'` `    ``for` `i ``in` `range``(``0``, len__, ``1``):` `        ``freq[``ord``(``str``[i]) ``-` `ord``(``'a'``)] ``+``=` `1`   `    ``# for each character, where character` `    ``# is obtained by (i + 'a') check whether ` `    ``# it is the maximum character so far and` `    ``# accodingly update 'result'` `    ``for` `i ``in` `range``(``26``):` `        ``if` `(``max` `< freq[i]):` `            ``max` `=` `freq[i]` `            ``result ``=` `chr``(``ord``(``'a'``) ``+` `i)`   `    ``# maximum occurring character` `    ``return` `result`   `# Driver Code` `if` `__name__ ``=``=` `'__main__'``:` `    ``str` `=` `"sample program"` `    ``print``(``"Maximum occurring character ="``,` `                 ``getMaxOccurringChar(``str``))` `    `  `# This code is contributed by` `# Surendra_Gangwar`

## C#

 `// C# implementation to find` `// the maximum occurring character in` `// an input string which is lexicographically first` ` `  `using` `System;` `class` `GFG {` ` `  `// function to find the maximum occurring character in` `// an input string which is lexicographically first` `    ``static` `char` `getMaxOccurringChar(``string` `str) {` `        ``// freq[] used as hash table` `        ``int``[] freq = ``new` `int``;` ` `  `        ``// to store maximum frequency` `        ``int` `max = -1;` ` `  `        ``// to store the maximum occurring character` `        ``char` `result = (``char``)0;` ` `  `        ``// length of 'str'` `        ``int` `len = str.Length;` ` `  `        ``// get frequency of each character of 'str'` `        ``for` `(``int` `i = 0; i < len; i++) {` `            ``if` `(str[i] != ``' '``) {` `                ``freq[str[i] - ``'a'``]++;` `            ``}` `        ``}` ` `  `        ``// for each character, where character is obtained by` `        ``// (i + 'a') check whether it is the maximum character` `        ``// so far and accodingly update 'result'` `        ``for` `(``int` `i = 0; i < 26; i++) {` `            ``if` `(max < freq[i]) {` `                ``max = freq[i];` `                ``result = (``char``) (i + ``'a'``);` `            ``}` `        ``}` ` `  `        ``// maximum occurring character` `        ``return` `result;` `    ``}` ` `  `// Driver Code` `    ``public` `static` `void` `Main() {` `        ``string` `str = ``"sample program"``;` `        ``Console.WriteLine(``"Maximum occurring character = "` `                ``+ getMaxOccurringChar(str));` `    ``}` `} `

## Javascript

 ``

Output:

`Maximum occurring character = a`

Time Complexity: O(n).
Auxiliary Space: O(1).
Source: Sabre Interview Experience | Set 2

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