Magic Square | ODD Order
A magic square of order n is an arrangement of n2 numbers, usually distinct integers, in a square, such that the n numbers in all rows, all columns, and both diagonals sum to the same constant. A magic square contains the integers from 1 to n2.
The constant sum in every row, column and diagonal are called the magic constant or magic sum, M. The magic constant of a normal magic square depends only on n and has the following value:
M = n(n2+1)/2
For normal magic squares of order n = 3, 4, 5, ..., the magic constants are: 15, 34, 65, 111, 175, 260, ...
In this post, we will discuss how programmatically we can generate a magic square of size n. This approach only takes into account odd values of n and doesn’t work for even numbers. Before we go further, consider the below examples:
Magic Square of size 3 ----------------------- 2 7 6 9 5 1 4 3 8 Sum in each row & each column = 3*(32+1)/2 = 15 Magic Square of size 5 ---------------------- 9 3 22 16 15 2 21 20 14 8 25 19 13 7 1 18 12 6 5 24 11 10 4 23 17 Sum in each row & each column = 5*(52+1)/2 = 65 Magic Square of size 7 ---------------------- 20 12 4 45 37 29 28 11 3 44 36 35 27 19 2 43 42 34 26 18 10 49 41 33 25 17 9 1 40 32 24 16 8 7 48 31 23 15 14 6 47 39 22 21 13 5 46 38 30 Sum in each row & each column = 7*(72+1)/2 = 175
Did you find any pattern in which the numbers are stored?
In any magic square, the first number i.e. 1 is stored at position (n/2, n-1). Let this position be (i,j). The next number is stored at position (i-1, j+1) where we can consider each row & column as circular array i.e. they wrap around.
Three conditions hold:
- The position of next number is calculated by decrementing row number of the previous number by 1, and incrementing the column number of the previous number by 1. At any time, if the calculated row position becomes -1, it will wrap around to n-1. Similarly, if the calculated column position becomes n, it will wrap around to 0.
- If the magic square already contains a number at the calculated position, calculated column position will be decremented by 2, and calculated row position will be incremented by 1.
- If the calculated row position is -1 & calculated column position is n, the new position would be: (0, n-2).
Example: Magic Square of size 3 ---------------------- 2 7 6 9 5 1 4 3 8 Steps: 1. position of number 1 = (3/2, 3-1) = (1, 2) 2. position of number 2 = (1-1, 2+1) = (0, 0) 3. position of number 3 = (0-1, 0+1) = (3-1, 1) = (2, 1) 4. position of number 4 = (2-1, 1+1) = (1, 2) Since, at this position, 1 is there. So, apply condition 2. new position=(1+1,2-2)=(2,0) 5. position of number 5=(2-1,0+1)=(1,1) 6. position of number 6=(1-1,1+1)=(0,2) 7. position of number 7 = (0-1, 2+1) = (-1,3) // this is tricky, see condition 3 new position = (0, 3-2) = (0,1) 8. position of number 8=(0-1,1+1)=(-1,2)=(2,2) //wrap around 9. position of number 9=(2-1,2+1)=(1,3)=(1,0) //wrap around
Based on the above approach, the following is the working code:
C++
// C++ program to generate odd sized magic squares #include <bits/stdc++.h> using namespace std; // A function to generate odd sized magic squares void generateSquare( int n) { int magicSquare[n][n]; // set all slots as 0 memset (magicSquare, 0, sizeof (magicSquare)); // Initialize position for 1 int i = n / 2; int j = n - 1; // One by one put all values in magic square for ( int num = 1; num <= n * n;) { if (i == -1 && j == n) // 3rd condition { j = n - 2; i = 0; } else { // 1st condition helper if next number // goes to out of square's right side if (j == n) j = 0; // 1st condition helper if next number // is goes to out of square's upper side if (i < 0) i = n - 1; } if (magicSquare[i][j]) // 2nd condition { j -= 2; i++; continue ; } else magicSquare[i][j] = num++; // set number j++; i--; // 1st condition } // Print magic square cout << "The Magic Square for n=" << n << ":\nSum of " "each row or column " << n * (n * n + 1) / 2 << ":\n\n" ; for (i = 0; i < n; i++) { for (j = 0; j < n; j++) // setw(7) is used so that the matrix gets // printed in a proper square fashion. cout << setw(4) << magicSquare[i][j] << " " ; cout << endl; } } // Driver code int main() { // Works only when n is odd int n = 7; generateSquare(n); return 0; } // This code is contributed by rathbhupendra |
C
// C program to generate odd sized magic squares #include <stdio.h> #include <string.h> // A function to generate odd sized magic squares void generateSquare( int n) { int magicSquare[n][n]; // set all slots as 0 memset (magicSquare, 0, sizeof (magicSquare)); // Initialize position for 1 int i = n / 2; int j = n - 1; // One by one put all values in magic square for ( int num = 1; num <= n * n;) { if (i == -1 && j == n) // 3rd condition { j = n - 2; i = 0; } else { // 1st condition helper if next number // goes to out of square's right side if (j == n) j = 0; // 1st condition helper if next number // is goes to out of square's upper side if (i < 0) i = n - 1; } if (magicSquare[i][j]) // 2nd condition { j -= 2; i++; continue ; } else magicSquare[i][j] = num++; // set number j++; i--; // 1st condition } // Print magic square printf ( "The Magic Square for n=%d:\nSum of " "each row or column %d:\n\n" , n, n * (n * n + 1) / 2); for (i = 0; i < n; i++) { for (j = 0; j < n; j++) printf ( "%3d " , magicSquare[i][j]); printf ( "\n" ); } } // Driver program to test above function int main() { int n = 7; // Works only when n is odd generateSquare(n); return 0; } |
Java
// Java program to generate odd sized magic squares import java.io.*; class GFG { // Function to generate odd sized magic squares static void generateSquare( int n) { int [][] magicSquare = new int [n][n]; // Initialize position for 1 int i = n / 2 ; int j = n - 1 ; // One by one put all values in magic square for ( int num = 1 ; num <= n * n;) { if (i == - 1 && j == n) // 3rd condition { j = n - 2 ; i = 0 ; } else { // 1st condition helper if next number // goes to out of square's right side if (j == n) j = 0 ; // 1st condition helper if next number is // goes to out of square's upper side if (i < 0 ) i = n - 1 ; } // 2nd condition if (magicSquare[i][j] != 0 ) { j -= 2 ; i++; continue ; } else // set number magicSquare[i][j] = num++; // 1st condition j++; i--; } // print magic square System.out.println( "The Magic Square for " + n + ":" ); System.out.println( "Sum of each row or column " + n * (n * n + 1 ) / 2 + ":" ); for (i = 0 ; i < n; i++) { for (j = 0 ; j < n; j++) System.out.print(magicSquare[i][j] + " " ); System.out.println(); } } // driver program public static void main(String[] args) { // Works only when n is odd int n = 7 ; generateSquare(n); } } // Contributed by Pramod Kumar |
Python3
# Python program to generate # odd sized magic squares # A function to generate odd # sized magic squares def generateSquare(n): # 2-D array with all # slots set to 0 magicSquare = [[ 0 for x in range (n)] for y in range (n)] # initialize position of 1 i = n / / 2 j = n - 1 # Fill the magic square # by placing values num = 1 while num < = (n * n): if i = = - 1 and j = = n: # 3rd condition j = n - 2 i = 0 else : # next number goes out of # right side of square if j = = n: j = 0 # next number goes # out of upper side if i < 0 : i = n - 1 if magicSquare[ int (i)][ int (j)]: # 2nd condition j = j - 2 i = i + 1 continue else : magicSquare[ int (i)][ int (j)] = num num = num + 1 j = j + 1 i = i - 1 # 1st condition # Printing magic square print ( "Magic Square for n =" , n) print ( "Sum of each row or column" , n * (n * n + 1 ) / / 2 , "\n" ) for i in range ( 0 , n): for j in range ( 0 , n): print ( '%2d ' % (magicSquare[i][j]), end = '') # To display output # in matrix form if j = = n - 1 : print () # Driver Code # Works only when n is odd n = 7 generateSquare(n) # This code is contributed # by Harshit Agrawal |
C#
// C# program to generate odd sized magic squares using System; class GFG { // Function to generate odd sized magic squares static void generateSquare( int n) { int [, ] magicSquare = new int [n, n]; // Initialize position for 1 int i = n / 2; int j = n - 1; // One by one put all values in magic square for ( int num = 1; num <= n * n;) { if (i == -1 && j == n) // 3rd condition { j = n - 2; i = 0; } else { // 1st condition helper if next number // goes to out of square's right side if (j == n) j = 0; // 1st condition helper if next number is // goes to out of square's upper side if (i < 0) i = n - 1; } // 2nd condition if (magicSquare[i, j] != 0) { j -= 2; i++; continue ; } else // set number magicSquare[i, j] = num++; // 1st condition j++; i--; } // print magic square Console.WriteLine( "The Magic Square for " + n + ":" ); Console.WriteLine( "Sum of each row or column " + n * (n * n + 1) / 2 + ":" ); for (i = 0; i < n; i++) { for (j = 0; j < n; j++) Console.Write(magicSquare[i, j] + " " ); Console.WriteLine(); } } // driver program public static void Main() { // Works only when n is odd int n = 7; generateSquare(n); } } // This code is contributed by Sam007. |
PHP
<?php // php program to generate odd sized // magic squares // A function to generate odd sized // magic squares function generateSquare( $n ) { // set all slots as 0 $magicSquare ; for ( $i = 0; $i < $n ; $i ++) for ( $j = 0; $j < $n ; $j ++) $magicSquare [ $i ][ $j ] = 0; // Initialize position for 1 $i = (int) $n / 2; $j = $n - 1; // One by one put all values in // magic square for ( $num = 1; $num <= $n * $n ; ) { // 3rd condition if ( $i == -1 && $j == $n ) { $j = $n -2; $i = 0; } else { // 1st condition helper if // next number goes to out // of square's right side if ( $j == $n ) $j = 0; // 1st condition helper if // next number is goes to // out of square's upper // side if ( $i < 0) $i = $n -1; } // 2nd condition if ( $magicSquare [ $i ][ $j ]) { $j -= 2; $i ++; continue ; } else // set number $magicSquare [ $i ][ $j ] = $num ++; // 1st condition $j ++; $i --; } // Print magic square echo "The Magic Square for n = " . $n . ":\nSum of each row or column " . $n * ( $n * $n + 1) / 2; echo "\n\n" ; for ( $i = 0; $i < $n ; $i ++) { for ( $j = 0; $j < $n ; $j ++) echo $magicSquare [ $i ][ $j ] . " " ; echo "\n" ; } } // Driver program to test above function // Works only when n is odd $n = 7; generateSquare ( $n ); // This code is contributed by mits. ?> |
Javascript
<script> // javascript program to generate odd sized magic squares // Function to generate odd sized magic squares function generateSquare(n) { magicSquare = Array(n).fill(0).map(x => Array(n).fill(0)); // Initialize position for 1 var i = parseInt(n / 2); var j = n - 1; // One by one put all values in magic square for (num = 1; num <= n * n;) { if (i == -1 && j == n) // 3rd condition { j = n - 2; i = 0; } else { // 1st condition helper if next number // goes to out of square's right side if (j == n) j = 0; // 1st condition helper if next number is // goes to out of square's upper side if (i < 0) i = n - 1; } // 2nd condition if (magicSquare[i][j] != 0) { j -= 2; i++; continue ; } else // set number magicSquare[i][j] = num++; // 1st condition j++; i--; } // print magic square document.write( "The Magic Square for " + n + ":<br>" ); document.write( "Sum of each row or column " + parseInt(n * (n * n + 1) / 2) + ":<br>" ); for (i = 0; i < n; i++) { for (j = 0; j < n; j++) document.write(magicSquare[i][j] + " " ); document.write( "<br>" ); } } // driver program // Works only when n is odd var n = 7; generateSquare(n); // This code is contributed by 29AjayKumar </script> |
The Magic Square for n=7: Sum of each row or column 175: 20 12 4 45 37 29 28 11 3 44 36 35 27 19 2 43 42 34 26 18 10 49 41 33 25 17 9 1 40 32 24 16 8 7 48 31 23 15 14 6 47 39 22 21 13 5 46 38 30
Time Complexity: O(n2)
Auxiliary Space: O(n2)
NOTE: This approach works only for odd values of n.
Please Login to comment...