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The log1p() function takes an argument x and returns the natural logarithm of the base-e logarithm of x+1. Here e is a mathematical constant with value equal to 2.71828.

Syntax:

```double log1p (double x);
float log1p (float x);
long double log1p (long double x);```

Parameter:

• The log1p() function takes a single argument in the range [-1, ?].
• If we pass the value which is less than -1, log1p() returns Nan (Not a Number).

Return:

• a positive number : if x > 0
• zero if x=0
• a negative number if -1 > x > 0
• -?(- infinity) if x=-1
• NaN if x<-1

Error and Exception:

1. It is mandatory to give both the arguments otherwise it will give error no matching function for call to ‘log1p()’.
2. If we pass the string as argument we will get error no matching function for call to ‘log1p(const char [n]).
3. It gives -inf if we pass -1.
4. It gives zero if we pass 0.

Examples:

```Input  : log1p(50.35)
Output :  3.93866```
```Input  : log1p(143)
Output : 4.96981```

# CODE 1

## CPP

 `// CPP program to illustrate log1p()` `#include ` `#include ` `using` `namespace` `std;`   `int` `main()` `{` `    ``double` `x = 50.35, answer;`   `    ``// returns logarithm of 51.35 base e` `    ``answer = log1p(x);` `    ``cout << ``"log1p("` `<< x << ``") = "` `        ``<< answer << endl;`   `    ``return` `0;` `}`

Output:

`log1p(50.35) = 3.93866`

Time Complexity: O(1)

Space Complexity:  O(1)

# CODE 2

## CPP

 `// CPP program to illustrate log1p()` `#include ` `#include `   `using` `namespace` `std;`   `int` `main()` `{` `    ``double` `answer;` `    ``int` `x = 143;`   `    ``// returns logarithm of 144 base e` `    ``answer = log1p(x);` `    ``cout << ``"log1p("` `<< x << ``") = "` `        ``<< answer << endl;`   `    ``return` `0;` `}`

Output:

`log1p(143) = 4.96981`

Time Complexity:O(1)

Space Complexity: O(1)

Practical usage:

• It is practically used to get logarithm value of given argument+1.

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