LINQ | How to find maximum value of the given sequence?

In LINQ, you can find the maximum element of the given sequence by using Max() function. This method provides the maximum element of the given set of values. It does not support query syntax in C#, but it supports in VB.NET. It is available in both Enumerable and Queryable classes in C#. It returns null if all the elements present in the collection are null. It returns any type of data type means you can also use Max with the collection of a custom type(does not contain numeric value), but for this, you have to implement the IComparable interface. It can work with nullable, non-nullable decimal, double, floats, int, etc. values.

Example 1:

// C# program to find maximum
// value from the given array
using System;
using System.Linq;

class GFG {

    // Main Method
    static public void Main()
    {

        // Data source
        int[] sequence = {20, 45, 50, 79, 90,
                       79, 89, 100, 567, 29};

        // Display the sequence
        Console.WriteLine("The sequence is:");
        foreach(int s in sequence)
        {
            Console.WriteLine(s);
        }

        // Finding the maximum element
        // from the given sequence
        // Using Max function
        int result = sequence.Max();
        Console.WriteLine("Maximum Value: {0}", result);
    }
}

Output:

The sequence is:
20
45
50
79
90
79
89
100
567
29
Maximum Value: 567

Example 2:

// C# program to find the Maximum
// salary of the employee
using System;
using System.Linq;
using System.Collections.Generic;

// Employee details
public class Employee {

    public int emp_id
    {
        get;
        set;
    }
    public string emp_name
    {
        get;
        set;
    }
    public string emp_gender
    {
        get;
        set;
    }
    public string emp_hire_date
    {
        get;
        set;
    }
    public int emp_salary
    {
        get;
        set;
    }
}

class GFG {

    // Main method
    static public void Main()
    {
        List<Employee> emp = new List<Employee>() {
            new Employee() { emp_id = 209, emp_name = "Anjita", emp_gender = "Female", emp_hire_date = "12/3/2017", emp_salary = 20000 },
                new Employee() { emp_id = 210, emp_name = "Soniya", emp_gender = "Female", emp_hire_date = "22/4/2018", emp_salary = 30000 },
                new Employee() { emp_id = 211, emp_name = "Rohit", emp_gender = "Male", emp_hire_date = "3/5/2016", emp_salary = 40000 },
                new Employee() { emp_id = 212, emp_name = "Supriya", emp_gender = "Female", emp_hire_date = "4/8/2017", emp_salary = 40000 },
                new Employee() { emp_id = 213, emp_name = "Anil", emp_gender = "Male", emp_hire_date = "12/1/2016", emp_salary = 40000 },
                new Employee() { emp_id = 214, emp_name = "Anju", emp_gender = "Female", emp_hire_date = "17/6/2015", emp_salary = 50000 },
        };

        // Find the Maximum salary of the
        // employee Using Max() method
        var res = emp.Max(a => a.emp_salary);
        Console.WriteLine("Maximum Salary of the Employee: {0}", res);
    }
}

Output:

Maximum Salary of the Employee: 50000