# Java Program to Rotate bits of a number

Bit Rotation: A rotation (or circular shift) is an operation similar to shift except that the bits that fall off at one end are put back to the other end.

In left rotation, the bits that fall off at left end are put back at right end.

In right rotation, the bits that fall off at right end are put back at left end.

Example:

Let n is stored using 8 bits. Left rotation of n = 11100101 by 3 makes n = 00101111 (Left shifted by 3 and first 3 bits are put back in last ). If n is stored using 16 bits or 32 bits then left rotation of n (000…11100101) becomes 00..00**11100101**000.

Right rotation of n = 11100101 by 3 makes n = 10111100 (Right shifted by 3 and last 3 bits are put back in first ) if n is stored using 8 bits. If n is stored using 16 bits or 32 bits then right rotation of n (000…11100101) by 3 becomes **101**000..00**11100**.

## Java

`// Java code to rotate bits ` `// of number ` `class` `GFG ` `{ ` `static` `final` `int` `INT_BITS = ` `32` `; ` ` ` `/*Function to left rotate n by d bits*/` `static` `int` `leftRotate(` `int` `n, ` `int` `d) { ` ` ` ` ` `/* In n<<d, last d bits are 0. ` ` ` `To put first 3 bits of n at ` ` ` `last, do bitwise or of n<<d with ` ` ` `n >>(INT_BITS - d) */` ` ` `return` `(n << d) | (n >> (INT_BITS - d)); ` `} ` ` ` `/*Function to right rotate n by d bits*/` `static` `int` `rightRotate(` `int` `n, ` `int` `d) { ` ` ` ` ` `/* In n>>d, first d bits are 0. ` ` ` `To put last 3 bits of at ` ` ` `first, do bitwise or of n>>d ` ` ` `with n <<(INT_BITS - d) */` ` ` `return` `(n >> d) | (n << (INT_BITS - d)); ` `} ` ` ` `// Driver code ` `public` `static` `void` `main(String arg[]) ` `{ ` ` ` `int` `n = ` `16` `; ` ` ` `int` `d = ` `2` `; ` ` ` `System.out.print(` `"Left Rotation of "` `+ n + ` ` ` `" by "` `+ d + ` `" is "` `); ` ` ` `System.out.print(leftRotate(n, d)); ` ` ` ` ` `System.out.print(" ` `Right Rotation of " + n + ` ` ` `" by "` `+ d + ` `" is "` `); ` ` ` `System.out.print(rightRotate(n, d)); ` `} ` `} ` ` ` `// This code is contributed by Anant Agarwal. ` |

**Output : **

Left Rotation of 16 by 2 is 64 Right Rotation of 16 by 2 is 4

**For 16 bit number:**

## Java

`/*package whatever //do not write package name here */` ` ` `import` `java.io.*; ` ` ` `class` `GFG { ` ` ` `public` `static` `void` `main (String[] args) { ` ` ` `int` `N=` `28` `; ` ` ` `int` `D=` `2` `; ` ` ` `rotate(N,D); ` ` ` `} ` ` ` `static` `void` `rotate(` `int` `N, ` `int` `D) ` ` ` `{ ` ` ` `// your code here ` ` ` `int` `t=` `16` `; ` ` ` `int` `left= ((N<<D) | N>>(t-D)) & ` `0xFFFF` `; ` ` ` `int` `right=((N>>D) | N<<(t-D)) & ` `0xFFFF` `; ` ` ` `System.out.println(left); ` ` ` `System.out.println(right); ` ` ` `} ` ` ` `} ` |

Output:

Left Rotation of 28 by 2 is 112 Right Rotation of 28 by 2 is 7

**Time Complexity **: O(1)

**Space Complexity **: O(1)

Please refer complete article on Rotate bits of a number for more details!