is_void template in C++
The std::is_void template of C++ STL is used to check whether the type is a void or not. It returns a boolean value showing the same.
Syntax:
template < class T > struct is_void;
Parameter: This template contains single parameter T (Trait class) to check whether T is a void type or not.
Return Value: This template returns a boolean value as shown below:
- True: if the type is a void.
- False: if the type is a non-void.
Below programs illustrate the std::is_void template in C++ STL:
Program 1:
// C++ program to illustrate // std::is_void template #include <iostream> #include <type_traits> using namespace std; // main program int main() { cout << boolalpha; cout << "is_void:" << '\n' ; cout << "void:" << is_void< void >::value << '\n' ; cout << "const void:" << is_void< const void >::value << '\n' ; cout << "int:" << is_void< int >::value << '\n' ; cout << "char:" << is_void< char >::value << '\n' ; return 0; } |
Output:
is_void: void:true const void:true int:false char:false
Program 2:
// C++ program to illustrate // std::is_void template #include <iostream> #include <type_traits> using namespace std; // main program int main() { cout << boolalpha; cout << "is_void:" << '\n' ; cout << "double:" << is_void< double >::value << '\n' ; cout << "float:" << is_void< float >::value << '\n' ; cout << "volatile void:" << is_void< volatile void >::value << '\n' ; cout << "const volatile void:" << is_void< const volatile void >::value << '\n' ; return 0; } |
Output:
is_void: double:false float:false volatile void:true const volatile void:true
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