How to Remove Duplicates from ArrayList in Java
Given an ArrayList with duplicate values, the task is to remove the duplicate values from this ArrayList in Java.
Examples:
Input: List = [1, 10, 2, 2, 10, 3, 3, 3, 4, 5, 5] Output: List = [1, 10, 2, 3, 4, 5] Input: List = ["G", "e", "e", "k", "s"] Output: List = ["G", "e", "k", "s"]
-
Using Iterator
Approach:
- Get the ArrayList with duplicate values.
- Create another ArrayList.
- Traverse through the first arraylist and store the first appearance of each element into the second arraylist using contains() method.
- The second ArrayList contains the elements with duplicates removed.
Below is the implementation of the above approach:
// Java program to remove duplicates from ArrayList
import
java.util.*;
public
class
GFG {
// Function to remove duplicates from an ArrayList
public
static
<T> ArrayList<T> removeDuplicates(ArrayList<T> list)
{
// Create a new ArrayList
ArrayList<T> newList =
new
ArrayList<T>();
// Traverse through the first list
for
(T element : list) {
// If this element is not present in newList
// then add it
if
(!newList.contains(element)) {
newList.add(element);
}
}
// return the new list
return
newList;
}
// Driver code
public
static
void
main(String args[])
{
// Get the ArrayList with duplicate values
ArrayList<Integer>
list =
new
ArrayList<>(
Arrays
.asList(
1
,
10
,
1
,
2
,
2
,
3
,
3
,
10
,
3
,
4
,
5
,
5
));
// Print the Arraylist
System.out.println(
"ArrayList with duplicates: "
+ list);
// Remove duplicates
ArrayList<Integer>
newList = removeDuplicates(list);
// Print the ArrayList with duplicates removed
System.out.println(
"ArrayList with duplicates removed: "
+ newList);
}
}
Output:ArrayList with duplicates: [1, 10, 1, 2, 2, 3, 3, 10, 3, 4, 5, 5] ArrayList with duplicates removed: [1, 10, 2, 3, 4, 5]
-
Using LinkedHashSet
A better way (both time complexity and ease of implementation wise) is to remove duplicates from an ArrayList is to convert it into a Set that does not allow duplicates. Hence LinkedHashSet is the best option available as this do not allows duplicates as well it preserves the insertion order.
Approach:
- Get the ArrayList with duplicate values.
- Create a LinkedHashSet from this ArrayList. This will remove the duplicates
- Convert this LinkedHashSet back to Arraylist.
- The second ArrayList contains the elements with duplicates removed.
Below is the implementation of the above approach:
// Java program to remove duplicates from ArrayList
import
java.util.*;
public
class
GFG {
// Function to remove duplicates from an ArrayList
public
static
<T> ArrayList<T> removeDuplicates(ArrayList<T> list)
{
// Create a new LinkedHashSet
Set<T> set =
new
LinkedHashSet<>();
// Add the elements to set
set.addAll(list);
// Clear the list
list.clear();
// add the elements of set
// with no duplicates to the list
list.addAll(set);
// return the list
return
list;
}
// Driver code
public
static
void
main(String args[])
{
// Get the ArrayList with duplicate values
ArrayList<Integer>
list =
new
ArrayList<>(
Arrays
.asList(
1
,
10
,
1
,
2
,
2
,
3
,
10
,
3
,
3
,
4
,
5
,
5
));
// Print the Arraylist
System.out.println(
"ArrayList with duplicates: "
+ list);
// Remove duplicates
ArrayList<Integer>
newList = removeDuplicates(list);
// Print the ArrayList with duplicates removed
System.out.println(
"ArrayList with duplicates removed: "
+ newList);
}
}
Output:ArrayList with duplicates: [1, 10, 1, 2, 2, 3, 10, 3, 3, 4, 5, 5] ArrayList with duplicates removed: [1, 10, 2, 3, 4, 5]
-
Using Java 8 Stream.distinct()
You can use the distinct() method from the Stream API. The distinct() method return a new Stream without duplicates elements based on the result returned by equals() method, which can be used for further processing. The actual processing of Stream pipeline starts only after calling terminal methods like forEach() or collect().
Approach:
- Get the ArrayList with duplicate values.
- Create a new List from this ArrayList.
- Using Stream().distinct() method which return distinct object stream.
- convert this object stream into List
Below is the implementation of the above approach:
// Java program to remove duplicates from ArrayList
import
java.util.ArrayList;
import
java.util.Arrays;
import
java.util.List;
import
java.util.stream.Collectors;
// Program to remove duplicates from a List in Java 8
class
GFG
{
public
static
void
main(String[] args)
{
// input list with duplicates
List<Integer> list =
new
ArrayList<>(
Arrays.asList(
1
,
10
,
1
,
2
,
2
,
3
,
10
,
3
,
3
,
4
,
5
,
5
));
// Print the Arraylist
System.out.println(
"ArrayList with duplicates: "
+ list);
// Construct a new list from the set constucted from elements
// of the original list
List<Integer> newList = list.stream()
.distinct()
.collect(Collectors.toList());
// Print the ArrayList with duplicates removed
System.out.println(
"ArrayList with duplicates removed: "
+ newList);
}
}
Output:ArrayList with duplicates: [1, 10, 1, 2, 2, 3, 10, 3, 3, 4, 5, 5] ArrayList with duplicates removed: [1, 10, 2, 3, 4, 5]
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