# How to create an array of zeros in Python?

• Last Updated : 22 Jun, 2022

In this article, we will discuss how to create an array of zeros in Python. In array items are stored at contiguous memory locations and here we will try to add only Zeros into the array with different methods.

Here we will cover different approaches to creating a zero’s element array. The different approaches that we will cover in this article are:

### Method 1: Using simple multiplication

In this example, we are multiplying the array of zero to 9. In return, we will get an array with 9 elements of 0’s.

## Python3

 `arr0 ``=` `[``0``] ``*` `9` `print` `(arr0)`

Output:

`[0, 0, 0, 0, 0, 0, 0, 0, 0]`

### Method 2: Using a loop

In this example, we are creating a 0’s array using a for loop of range from 0 to 10.

## Python3

 `arr1 ``=` `[]` `for` `i ``in` `range``(``0``,``10``):` `    ``arr1.append(``0``)` `    `  `print``(arr1)`

Output:

`[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]`

### Method 3: Using List comprehension

Example 1: Creating 1D array using list comprehension

As we know here for loop will generate such a list, and we iterate zero within the list till the given range.

## Python3

 `arr ``=` `[``0` `for` `element ``in` `range``(``5``)]` `print``(arr)`

Output:

`[0, 0, 0, 0, 0]`

Example 2: Creating 2D array using list comprehension

In this example, we are creating a 2-D array using a list comprehension in python to create 0’s of 5 rows and 10 columns.

## Python3

 `arr2 ``=` `[[``0` `for` `col ``in` `range``(``5``)] ``for` `row ``in` `range``(``10``)]` `print``(arr2)`

Output:

```[[0, 0, 0, 0, 0],
[0, 0, 0, 0, 0],
[0, 0, 0, 0, 0],
[0, 0, 0, 0, 0],
[0, 0, 0, 0, 0],
[0, 0, 0, 0, 0],
[0, 0, 0, 0, 0],
[0, 0, 0, 0, 0],
[0, 0, 0, 0, 0],
[0, 0, 0, 0, 0]]```

### Method 4: Using the In-Build method numpy.zeros() method

In this example, we are creating a NumPy array with zeros as the numpy.zeros() function is used which returns a new array of given shape and type, with zeros.

## Python3

 `import` `numpy as np`   `# Specifying array as a tuple, and ` `# Specify their data types.` `arr3 ``=` `np.zeros((``2``, ``2``, ``3``), dtype``=``[(``'x'``, ``'int'``), (``'y'``, ``'float'``)])` `print``(arr3)` `print``(arr3.dtype)`

Output:

In the output, i4 specifies 4 bytes of integer data type, whereas f8 specifies 8 bytes of float data type.

```[[[(0, 0.) (0, 0.) (0, 0.)]
[(0, 0.) (0, 0.) (0, 0.)]]

[[(0, 0.) (0, 0.) (0, 0.)]
[(0, 0.) (0, 0.) (0, 0.)]]]
[('x', '<i4'), ('y', '<f8')]```

### Method 5: Using  itertools.repeat() Function

Itertools module is a memory-efficient tool that is used either by itself or in combination to form iterator algebra.

Here we create an iterator using repeat() function, this function takes the value as its first argument, and then the second argument take the number of repetition of the values.

Below the example, we take 0 as a value and the second parameter 5 is the number of repetitions and then convert the temp_var into list.

## Python3

 `# import module` `import` `itertools`   `# create instance with repeat()` `# value = 0 and range = 5` `temp_var ``=` `itertools.repeat(``0``,``5``)` `print``(``list``(temp_var))`

Output:

`[0, 0, 0, 0, 0]`

My Personal Notes arrow_drop_up
Recommended Articles
Page :